Finding mode for Grouped Data when class intervals are given
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The following data shows monthly savings of 100 families . Calculate the mode of the given frequency distribution.
Monthly savings(Rs) Number of families 1000−2000142000−3000153000−4000214000−5000275000−600025
4790
4750
4760
4780
Find the mode
Class interval100−110110−120120−130130−140140−150Frequency89111210
The following data shows the warranty period of different components. Find the modal warranty period.
Warranty period(years)0−11−22−33−44−55−6Number of components61016251620
- 3
- 3.25
- 3.5
- 4
Find the mode of the following data. Class interval0−1010−2020−3030−4040−50Frequency71314511
- 25
- 20
- 30
- 21
Find the mode of the following data.
Class interval0−100100−200200−300300−400400−500Frequency7111598
A survey was conducted on 20 families in a locality by a group of students .What will be the mode of the data?
Age of family member0−2020−4040−6060−8080−100 Number of students78221
21.85
24.87
23.87
22.86
For the following distribution, the modal class is
MarksNumber of studentsBelow 103Below 2012Below 3027Below 4057Below 5075Below 6080
10-20
30-40
50-60
20-30
The class interval size and frequency of the modal class is
Class Frequency 0−52005−1025010−1522515−2030020−25275
- 5 , 250
- 5, 300
- 4, 250
- 4, 200
The following data gives the information on the observed lifetime (in hours) of 225 electrical components:
Life time (in hours)0−2020−4040−6060−8080−100100−120Number of components103552613829
Determine the modal lifetime of the components.
60.02
65.69
66.21
65.62
A survey was conducted on 20 families in a locality by a group of students .What will be the mode of the data?
Age of family member0−2020−4040−6060−8080−100Number of students78221
21.8
22.85
25
27.88
The class size and frequency of modal class is
Warranty period(years)0−11−22−33−44−55−6Number of components61016251620
1 , 25
1 , 20
0 , 25
0 , 20
- unimodal, dual modal
- unimodal, multimodal
- unimodal, bi modal
- Both A and C
