Frequency Table
Trending Questions
Construct the frequency table for each of the following.
4, 3, 6, 5, 2, 4, 3, 3, 6, 4, 2, 3, 2, 2, 3, 3, 4, 5, 6, 4, 2, 3, 4
Data23456Frequency47625
Data23456Frequency75623
Data23456Frequency57623
Data23456Frequency57733
If the cumulative frequency for the class interval (30-40) is 70 and for class interval (50-60) is 150 , then the value of y =
Class Interval0−1010−2020−3030−4040−5050−60Frequency 12 20 x 18 10 y
20
80
70
50
Which of the following is the frequency distribution table for the following distributions?
Marks (more than)Cumulative Frequency0100108720653055404250366031702180189071000
Marks (more than)Cumulative Frequencyfrequency0−101001310−20872220−30651030−40551340−5042650−6036560−70311070−8021380−90181190−10077total100
Marks (more than)Cumulative Frequencyfrequency0−101002210−20871320−30651330−40551040−5042550−6036660−7031370−80211080−9018790−100711total100
Marks (more than)Cumulative Frequencyfrequency0−101002210−20871020−30651330−40551340−5042550−60361060−7031670−8021380−9018790−100711total100
Marks (more than)Cumulative Frequencyfrequency0−101001310−20872220−30651330−40551040−5042650−60361060−7031570−80211180−9018390−10077total100
The chart shows the number of sunny days and the number of windy days in six months. Ratio of sunny days in june to windy days in october is
MAY
OCT
JUNE
MAY, OCT
The Marks range of the Students in a class is from 0 to 80 out of a total of 80 marks. The Students have been categorized into groups of 10. The following frequency of the number of students in the Marks ranges (in ascending order) have been given:
2, 3, 6, 12, 8, 5, 7, 4
Which of the following Frequency distribution table corresponds to the Data given?
Marks rangeNo.of students0−10210−20320−30630−401240−50750−60560−70870−804
Marks rangeNo.of students0−10310−20220−30630−401240−50850−60560−70770−804
Marks rangeNo.of students0−10210−20320−30630−401240−50850−60560−70770−804
Marks rangeNo.of students0−10210−20320−30630−401240−50850−60760−70570−804
Number of CupsFrequencyCumulative Frequency2113344−−−−957166420
For the above given frequency table, find the missing frequency.
7
6
5
4
A survey was done in a Housing Society where the number of Vehicles were categorized according to their Mileage.
The Graph Given shows the Histogram for the Mileage vs The number of vehicles present.
Which of the Following Frequency distribution table is correct for the Graph?
- Mileage(km/l)No.of vehicles0−10610−20920−30830−401540−501150−60360−705
- Mileage(km/l)No.of vehicles0−10610−20920−30730−401540−501150−60360−705
- Mileage(km/l)No.of vehicles0−10610−20920−30830−401540−501050−60360−705
- Mileage(km/l)No.of vehicles0−10610−20920−30730−401540−501150−60460−705
The following table shows the class mark and frequency. Convert the table in the class interval
Class MarkFrequency558656751885259512
Class IntervalFrequency50−60860−70670−801880−902590−10012
Class IntervalFrequency40−50850−60660−701870−802580−9012
Class IntervalFrequency50−60860−70670−751875−802580−9012
class mark and class interval table will be the same
Which among the following is the correct histogram for the following data:
Class interval30−3940−4950−5960−6970−79Frequency241691520
A survey was done in a Housing Society where the number of Vehicles were categorized according to their Mileage.
The Graph Given shows the Histogram for the Mileage vs The number of vehicles present.
Draw the frequency distribution table for the given Graph?
Represent the given set in Roster form.
A = {x:x is an integer, −32<x<112}
{-3, -2, -1, 0, 1, 2, 3, 4, 5}
{-1, 0, 1, 2, 3, 4, 5}
{-1, 0, 1, 2, 3, 4, 5, 6}
{-2, -1, 0, 1, 2, 3, 4, 5}
Find the values of p, q, r and s in the given cumulative frequency distribution.
xfrequencyCumulative frequency103p=−−−−1510q=−−−−2025r=−−−−257s=−−−−30550
p = 0, q = 10, r = 35, s = 42
p = 3, q = 13, r = 38, s = 45
p = 3, q = 13, r = 35, s = 42
p = 3, q = 13, r = 28, s = 35
A company manufactures car batteries of a particular type. The lives (in years) of 40 such batteries were recorded as follows:
2.63.03.73.22.24.13.54.53.52.33.23.43.83.24.63.72.54.43.43.32.93.04.32.83.53.23.93.23.23.13.73.44.63.83.22.63.54.22.93.6
Construct a grouped frequency distribution table for this data, using class intervals of size 0.5 starting from the intervals 2−2.5. Calculate the number of batteries having a life of 3.5-4.0 years.
Look at the given Table and identify the correct Histogram which can be made using the data.
MarksNo.of students0−10210−20520−30930−40440−506
Take SCALE as : X-axis - 1cm = 10 Marks and Y-axis - 1cm = 2 students
Look at the given Table and identify the correct Histogram which can be made using the data.
MarksNo.of students0−10210−20520−30930−40440−506
Take SCALE as : X-axis - 1cm = 10 Marks and Y-axis - 1cm = 2 students
(a) Use the information given in the adjoining histogram to construct a frequency table.
(b) Use this table to construct an ogive.
[4 Marks]
The table below shows the sale of shirts of various sizes in a week.
Shirt size3839404142Number sold6073899023
The size which is demanded the most is
A survey was done in a Housing Society where the number of Vehicles were categorized according to their Mileage.
The Graph Given shows the Histogram for the Mileage vs The number of vehicles present.
Which of the Following Frequency distribution table is correct for the Graph?
Mileage(km/l)No.of vehicles0−10610−20920−30730−401540−501150−60460−705
Mileage(km/l)No.of vehicles0−10610−20920−30830−401540−501050−60360−705
Mileage(km/l)No.of vehicles0−10610−20920−30830−401540−501150−60360−705
Mileage(km/l)No.of vehicles0−10610−20920−30730−401540−501150−60360−705
We must catch the 5 o'clock train. There is only half an hour left. We must start without further delay. [Advanced]
- We must catch the 5 o' clock train and there being only half an hour left, we must start without further delay.
- We must catch the 5 o' clock train as there is only half an hour left. So we must start without further delay.
- We must catch the 5 o' clock train with there being only half an hour left, we must start without further delay.
- None of the above.
