Fundamental Theorem of Arithmetic
Every composite number can be factorised as a product of primes.
Every even positive integer is of the form (a)
(x is any positive integer)
- a=2x3, b=2x+2
- a=2x2, b=2x+1
- a=2x, b=2x+1
- a=x, b=3x+1
If p=2a×3b×5c and a>b>c are natural numbers, then what is the unit digit of p?
If 2 and 5 are factors of a number, what will be the unit’s digit of that number?
Check whether 6n can end with the digit 0 for any natural number n. [2 MARKS]
For what value of ‘n’ would 4n end with zero?
It will not end with zero for any value of n.
p = 22.32.q2 (where q is a prime < 7) is the prime factorisation representation of ‘p’. What is the value of p?
p = 700
p = 36
p = 900
Consider the number 4n, where n is a natural number. Check whether there is any value of n for which 4n ends with the digit zero. [2 MARKS]
Express as product of its prime factors : 156
1400n is NOT divisible by which of the following, if n is a natural number: