LCM of Polynomials
Trending Questions
- (x−1)(x−2)
- (x−1)(x−2)(x−7)
- (x−2)(x−7)
- (x−1)(x−7)
- 3xyzabc
- 8xyzabc
- 9xyzabc
A binomial may have degree 5
True
False
Use Euclids division algorithm to find the HCF of:
What is the LCM of (x2+5x+6) and (x2+7x+10)
(x + 2)
(x + 3)
(x + 2)(x + 3)
(x + 2)(x + 3)(x + 5)
Which among the following is a binomial of degree 100?
- 100x+1
- 100x2−3x+2
- x100−100
- x100−x+12
LCM and HCF of (x+1)2 and x3+1 are ____.
HCF = (x−1)
LCM = (x+1)(x2−x+1)
HCF = (x+1)
LCM = (x+1)(x2−x−1)
HCF = (x+11)
LCM = (x+1)(x2−5x+1)
HCF = (x+1)
LCM = (x+1)2(x2−x+1)
- 144
- 72
- 36
- 180
Use Euclids Division Algorithm to find HCF of:
and
- (x−3)(x−5)(x−7)
- (x−3)(x−5)
- (x−3)(x−7)
- (x−5)(x−7)
- 3(x−3)
- 3(x−3)(x+4)
- 3(x−3)
- 3(x−3)2
L.C.M. of 6x2−x−1, 3x2+7x+2 and 2x2+3x−2 is (x+2)(2x−1)(3x+1)
True
False
Use Euclids Division Algorithm to find HCF of:
The LCM of v2−v, (v−1)2, and v3−1 is
v(v+1)(v−1) (v2+v+1)
v2(v+1)(v−1) (v2+v+1)
v(v+1)(v−1)
v(v−1) (v2+v+1)
If the polynomials x3 + 3x2 − m and 2x3 − mx + 9 leave the same remainder when they are divided by (x − 2), find the value of m. Also find the remainder.
5, 15
3, 12
3, 15
5, 12
LCM of v2−v, v2−12, and v3−1
v(v+1)(v−1) (v2+v+1)
v2(v+1)(v−1) (v2+v+1)
v(v+1)(v−1)
v(v−1) (v2+v+1)
Use Euclid’s Division Algorithm to show that the squares of following numbers is either of form 3m or 3m + 1 for some integer m.
253
LCM of x2+x−6 and (x−2)2 is (x+a) (x−b)2. Value of (a+b)2 =
16
25
36
49
- (x−3)2(x+4)2
- (x−3)(x+4)2
- (x−3)(x+4)
- (x−3)2(x+4)
What is the LCM of (2a+3b)2 and (4a2–9b2)
(2a – 3b)
(2a – 3b) (2a +3b) 2
(2a – 3b) (2a +3b)
(2a +3b) 2
- 3
- 6
- \N
- 9
- x2y2(1−y)
- 18x2yz
- x3
- x(x−1)2