Mean of Ungrouped Data
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The marks obtained by the students of a class , in a exam which was out of 50 mark given below
Marks Number of students5172112163215246283325348396434452493
(i) Find the mean for the ungrouped data.
(ii) Represent the same data as grouped data, with class interval of width = 10 [4 MARKS]
The mean of the following distribution is ____.
xi10131619fi2576
15.2
15.35
15.55
16
- 2.6
- 2.5
- 3
- 2
If the mean of the following data is 20 then the value of p is ___
xi10p182125fi1015799
24
13
11
12
If the mean of the following data is 17 then the value of p is
xi10p182125fi1015799
The marks obtained by 40 students in mathematics (out of 100) is presented in the table below. Find the mean using direct method.
Class Interval0−1010−2020−3030−4040−50Number of students3413155
28.75
25.2
26.4
29.9
250 students of class X of a school appeared in a test of 100 marks and the data about the marks secured is as below.
Marks Secured0−2020−4040−6060−8080−100Number of students2035656070
If the mean of the following data is 17, then the value of 'p' is
xi10p182125fi1015799
15
24
16
14
The marks obtained by 40 students in mathematics (out of 100) is presented in the table below. Find the mean.
Class Interval0−1010−2020−3030−4040−50Number of students3413155
28.75
25.2
26.4
29.9
The formula for finding mean by direct method is ∑(A×B)∑A
Where B and A are respectively:
class mark, frequency of the class
Class size, average frequency
Frequency of the class, class mark
Average frequency, class size
∑fx = 5x + 2, ∑f = 12. If the mean of the distribution is 6, what is the value of x?
14
15
18
12
∑ fx=5x+2, ∑ f=12. If the mean of the distribution is 6, what is the value of x?
18
12
15
14
Find the frequency of 40 in the following given set of data.
10, 40, 80, 100, 60, 40, 30, 40, 20, 40.
3
1
2
4
If the mean of the following data is 17 then the value of p is
xi10p182125fi1015799
A person recorded the speed (in km/hr) of 10 motorists as 48, 52, 57, 55, 45, 39, 61, 49, 51 and 43. The average speed of the motorists is
55 km/hr
54 km/hr
50 km/hr
57 km/hr
If the mean of the following data is 17 then the value of p is
xi10p182125fi1015799
- A
- B
- C
- D
The formula for finding mean by direct method is
∑(A×B)∑A
where B and A are respectively are _______.
- frequency of the class, class mark
- class size, average frequency
- average frequency, class size
- class mark, frequency of the class
xf4108111291613
- 10
- 10.33
- 43
- 444
The formula for finding mean by direct method is
∑(A×B)∑A
where B and A are respectively are _______.
- class mark, frequency of the class
- frequency of the class, class mark
- class size, average frequency
- average frequency, class size
Find ∑fixi from the given table.
- 444
- 208
- Data inadequate
- 434
Obtain the mean of the following distribution.
Frequency | Variable |
The marks obtained by the students of a class, in an exam which was out of 50 marks is given below :
MarksNumber of students5172112163215246283325348396434452493
Find the mean for the ungrouped data.
29.94
24
28
30.5
Find the mean.
xi1014182125fi1015799
The formula for finding mean by direct method is
∑(A×B)∑A
where B and A are respectively are _______.
- class size, average frequency
- class mark, frequency of the class
- average frequency, class size
- frequency of the class, class mark
The mean of the following distribution is
xi10131619fi2576
15.35
15.55
16
15.2
A person recorded the speed (in km/hr) of 10 motorists as 48, 52, 57, 55, 45, 39, 61, 49, 51 and 43. The average speed of the motorists is
57 km/hr
50 km/hr
55 km/hr
54 km/hr
∑gx = 8y + 18, ∑g = 10. If the mean of the distribution is 5 , what is the value of y?
12
14
15
18
2, 3, 4, 5, 6
in these obtained marks, 4 is the
- Mean and median
- Mean but no median
- Median but no mean
- Mode
The mean of the following distriution is
xi10131619fi2576
15.2
15.35
15.55
16