Properties of GP
Trending Questions
If , then an ordered pair is equal to
Let and be the roots of , with . For all positive integers , define
and
Then which of the following options is/are correct?
If a+b+c=0, then the value of (a+b−c)3+(b+c−a)3+(c+a−b)3 is:
8(a3+b3+c3)
a3+b3+c3
24 abc
−24 abc
The sum of a few terms of any ratio series is , if the common ratio is and the last term is , then the first term of the series will be
The ratio of one Micron to one Nanometre is,
If , find the ratio .
How many terms of the series 3, 9, 27 . . . . . . . will add up to 363?
There is a natural numberx. Write down the expression for the product of xand its next natural number.
(x + 1)(x+2)
x2 + x
x2 -x
2x2 +1
If a, b, c are in A.P., a, x, b are in GP and b, y, c are also in G.P, then x2, b2, y2 are in AP.
True
False
The number which should be added to 2, 14 and 62 so that the resulting numbers are in G.P. is ___.
4
1
2
3
Find the term of the GP : .
How many terms of the series must be taken to make .
If 5, 15, 45, 135, 405, 1215.... are in GP, which series is also in GP?
5, 15, 405
5, 45, 405
5, 135, 405
5, 15, 135
If the sum of the 33+73+113+153...................20 terms is S20. Find the value of S20100 .
In the given G.P find the product of the fifth term from the begining and from the end.
116, 14, 1, 4, 16.........16, 384.
256
4096
4056
1024
The terms of any G.P are in:
G.P
A.P
H.P
A.G.P
If a, b, c, and d are in G. P., then (a+b)2 , (b+c)2 , and (c+d)2 are also in G. P.
True
False
If 56Pr+6:54Pr+3=30800:1, then r = 41
31
41
If a, b and c are in A.P. and also in G.P., show that : a = b = c .
- 4l2mn
- 4lm2n
- lmn2
- l2m2n2
How do you write ( repeating) as a fraction?
If a, b and c are in A.P, a, x, b are in G.P. whereas b, y and c are also in G.P. Show that : x2, b2, y2 are in A.P.
If a - 14, a - 2, a + 34 are in G.P, find the value of a.
- a=12, b=3
- a=4, b=16
- a=3, b=12
- a=2, b=32
The value of x for which the numbers 2x+1, 5x+1, and 11x+1 are in G.P is
If a, b, c are in G.P, then log a, log b and log c are in ____
- a(b2 + c2) = c(a2 + b2)
- a2(b + c) = c2(a + b)
- none of these
- a(b2 + c2) = c(b2 + c2)
Then prove that ab+c, bc+a, ca+b are in A.P