Regular and Irregular Class Interval
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The steps to convert an irregular class interval into a regular one, are
Step 1: Compute correction factor which is upper class limit-lower class limit of previous class interval2.
Step 2: This is added to the upper limit and subtracted from the lower limit of each class.
Step 1 is correct, but step 2 is incorrect.
Step 1 is incorrect, but step 2 is correct.
Both steps are correct
Both steps are incorrect.
Draw a cumalitive frequency curve (ogive) for each of the following distributions :
(i) Class interval10−1515−2020−2525−3030−3535−40Frequency10151712108
(ii) Class interval10−1920−2930−3940−4950−59Frequency2316152012
[4 Marks]
Assertion: We find midpoints of a class interval with the following formula.
upper class limit+lower class limit2
Reason: To draw frequency polygons independently without drawing histogram it is required to have the class mark.
Which of the following is correct?
A is true and R is false
Both A and R are true and R is the correct explanation of A
A is false and R is true
Both A and R are true but R is not the correct explanation of A