Solving a Quadratic Equation Using Formula
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The number of the real roots of the equation is
Solve the following quadratic equation using quadratic formula .
9x2−9(a+b)x+(2a2+5ab+2b2)=0
The roots are 2a+b3 and a+2b3
The roots are 2a+b3 and a−2b3
The roots are 5a+b3 and a+2b3
The roots are 2a+b3 and a−2b4
Sum of the first
20
19
21
18
Question 2 (i)
Find the values of k for each of the following quadratic equations, so that they have two equal roots.
(i)2x2+kx+3=0
If from a positive number, twice its reciprocal is subtracted, we get 1. Then the number is ___.
4
3
1
2
Using quadratic formula find the roots of the quadratic equation 2x2−7x+3=0 .
x=32
x=12
x=3
x=−3
5x2−3x−4=0
b)
Without solving the following quadratic equation, find the value of p for which the roots are equal:
px2−4x+3=0
- 2
- 3
- 0
- 1
- The roots are 2a+b3 and a+2b3
- The roots are 2a+b3 and a−2b3
- The roots are 5a+b3 and a+2b3
- The roots are 2a+b3 and a−2b4
3√2x2−5x−√2=0
- 720 km/h
- 730 km/h
- 740 km/h
- 750 km/h
A plane left 30 minutes later than the scheduled time and in order to reach its destination 1500 km away in time it has to increase its speed by 250 km/hr from its usual speed. Find its usual speed.
Find the roots of the quadratic equations given in Q.1 above by applying the quadratic formula.
(iii) 4x2+4√3x+3=0
2x2+5x−3=0 ?
x2−6x+3=0
- x=−b±√b2−4ac2
- x=−b−√b2−4ac4a
- x=−b+√b2−4ac4a
- x=−b±√b2−4ac2a
- −13
- -3
- 13
- 2
x−1x=3, x≠0
x2−4x+1=0
9x2−9(a+b)x+(2a2+5ab+2b2)=0
- 3 kmph
- 4 kmph
- 2 kmph
- 5 kmph