Standard Deviation of Ungrouped Data by Assumed Mean Method
Trending Questions
Q. The mean and standard deviation of the marks of 200 candidates were found to be 40 and 15 respectively. Later, it was discovered that a score of 40 was wrongly read as 50. The correct mean and standard deviation respectively are:
- 14.98, 39.95
- 39.95, 14.98
- 39.95, 224.5
- None the these
Q. The marks scored by 5 students in a class are 25, 30, 35, 40 and 45. Find the standard deviation using Assumed mean method.
- 7.07
- 8.12
- 3.21
- 6.12
Q. The number of filler units sold in 5 consecutive days are 5, 8, 10, 12, 15. Find the standard deviation using Assumed mean method.
- 6.59
- 8.25
- 4.42
- 5.23
Q. The marks scored by 5 students in a class are 25, 30, 35, 40 and 45. Find the standard deviation using Assumed mean method.
- 7.07
- 3.21
- 8.12
- 6.12
Q. Find the mean of the following frequency distribution using steps deviation method.
| C.I | 0-100 | 100-200 | 200-300 | 30-400 | 400-500 | 500-600 | 600-700 |
| F | 10 | 15 | 25 | 25 | 10 | 10 | 5 |
Q. Find the mean marks from the following data(nearest integer)
| Marks | No. of Students |
| Below 10 | 5 |
| Below 20 | 9 |
| Below 30 | 17 |
| Below 40 | 29 |
| Below 50 | 45 |
| Below 60 | 60 |
| Below 70 | 70 |
| Below 80 | 78 |
| Below 90 | 83 |
| Below 100 | 85 |
