Subset and Superset of a Set
Trending Questions
Q. Let S = {1, 2, 3, 4}. The total number of unordered pairs of disjoint subsets of S is equal to
- 25
- 41
- 34
- 42
Q. The cardinality of set P is 3. What is the number of elements in the power set of set P ?
- 8
Q. Given set A = {x : x is a vowel}. Identify the subsets of set A.
- {a, e}
- { }
- {a, b, c}
- {a, e, i, o, u}
Q.
Define cardinality of a set.
Q.
If A = {set of whole numbers less than 6} and B = {set of prime natural numbers less than 7}, then _________ .
A is a superset of B
A and B are disjoint sets
A is a subset of B
B is a superset of A
Q. Observe the Venn diagram given below and choose the correct statement(s).
- Set A is a subset of set B.
- Set B is a subset of set A.
- A∪B=B
- A∩B=A
Q. If set E = {a, b, c, d, e} and set A = {a, b, c}, then what is A ?
- Universal set
- Power set
- Null set
- Subset of E
Q. If A and B are subsets of the universal set U, then which of the following is/are true?
- A ⊂ (A ∪ B)
- A ⊂ B ⇔ (A ∪ B) = B
- (A ∩ B) ⊂ A
- A and B cannot be subsets of each other.
Q. If A = { x:x is an even natural number} and B = { y:y is a natural number}, then _______________.
- A is a subset of B
- B is a subset of A
- A is the superset of B
- B is the superset of A
Q. List all subsets of the following set.
L = {x : x is the letter in the word ‘dog’}.
L = {x : x is the letter in the word ‘dog’}.
Q.
Find the cardinality of the given set:
.
Q.
If ∪ = {2, 4, 6, 8, 10, 12, 14, 17} and A = {1, 4, 6, 9, 11, 12}, then set AC is
{2, 8, 10, 14, 17}
{2, 8, 10, 14, 17}
Can't be determined
{1, 2, 8, 10, 14, 17}
Q. Classify the following set as 'singleton' or 'empty': C={x|x is natural number, 5<x<7}
- Empty
- Singleton
- None of these
- Data insufficient
Q.
Every set is ________.
a subset of itself
a subset of a null set
a subset of other sets
a disjoint set
Q.
If A={2, 4, 6, 8, 10, 12}, B={4, 6, 8} and C={4, 6}, then which of the following statements are correct?
B⊆A
A⊇C
A⊇B
B⊆C
Q. Power set of a set is a set of all elements of the given set.
- True
- False