Sum of Pair of Opposite Angles in Quadrilateral
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In figure, if ∠AOB=125∘. Then ∠ COD is equal to
(A) 62.5°
(B) 45°
(C) 35°
(D) 55°
In the trapezium ABCD, the measure of ∠D is
a) 55∘
b) 115∘
c) 135∘
d) 125∘
Which of the following cannot be a cyclic quadrilateral?
Square
Rectangle
Parallelogram
Trapezium
In a cyclic quadrilateral ABCD, the diagonal AC bisects the ∠BCD. Prove that the diagonal BD is parallel to the tangent to the circle at point A.
If the sum of a pair of opposite angles of a quadrilateral is 180∘, then the quadrilateral is
Parabolic
Cyclic
Both cyclic and parabolic
Can't say
Two circles intersect each other at points A and B. A straight line PAQ cuts the circles at P and Q. If the tangent at P and Q intersect at point T; show that the points P, B, Q and T are concyclic.
Prove that opposite sides of a quadrilateral circumscribing a circle subtend supplementary angles at the center of the circle.
ABCD is a cyclic quadrilateral. Then which of the angles given add to 180∘?
1
2
- 3
- 4
In the figure, given below, AD = BC,
∠ BAC=30∘ and ∠CBD=70∘. Find: ∠ ADB
10∘
70∘
50∘
80∘
- 0
- 1
- 2
- −1
- 20o&130o
- 30o&130o
- 20o&120o
- 15o&130o
Prove that opposite sides of a quadrilateral circumscribing a circle subtend supplementary angles at the center of the circle.
In the given figure, ABCD is a cyclic quadrilateral, OB is the radius, PB is the tangent at point B and ∠OBC=30∘. AOC is a straight line. Then, the value of x is
60∘
30∘
120∘
90∘
ABCD is a cyclic quadrilateral BA and CD produced, meet at E . Prove that ΔEBC and ΔEDA are equiangular.
- 105∘
- 65∘
- 95∘
- 75∘
- ∠A=35o, ∠B=75o, ∠C=95o, ∠D=135o
- ∠A=65o, ∠B=55o, ∠C=115o, ∠D=125o
- ∠A=25o, ∠B=45o, ∠C=105o, ∠D=135o
- ∠A=45o, ∠B=75o, ∠C=95o, ∠D=125o
In the given figure, ABCD is a cyclic quadrilateral, OB is the radius, PB is the tangent at point B and ∠OBC=30∘. AOC is a straight line. Then, find the value of x.
If ∠BCD=50∘, then ∠BAD = ___.
- 50∘
- 100∘
- 25∘
- 70∘
In the given figure, O is the centre of the circle and ∠ ABC=55∘. Calculate the values of x and y.
x=110∘
y=225∘
x=110∘
y=125∘
x=100∘
y=125∘
x=100∘
y=120∘
- 70o
- 20o
- 60o
- 120o
In the given figure, ABCD is a cyclic quadrilateral, OB is the radius, PB is the tangent at point B and ∠OBC=30∘. AOC is a straight line. Then, the value of x is
60∘
30∘
120∘
90∘
In the given figure, ABCD is a cyclic quadrilateral, OB is the radius, PB is the tangent at point B and ∠OBC=30∘. AOC is a straight line. Then, the value of x is
60∘
30∘
120∘
90∘
To draw a pair of tangents to a circle which are inclined to each other at an angle of 60∘, it is required to draw tangents at endpoints of those two radii of the circle, the angle between them should be
(A) 135∘
(B) 90∘
(C) 60∘
(D) 120∘
A tangent PA is drawn from an external point P to a circle of radius 3√2 cm such that the distance of the point P from O is 6 cm as shown in the figure. The value of ∠APO is
- 30∘
- 45∘
- 60∘
- 75∘
If a pair of opposite sides of a cylic quadrilateral are equal, prove that its diagonals are equal. [3 MARKS]
ABCD is a quadrilateral such that ∠ABC+∠ADC =180∘. Inside the quadrilateral :
Statement 1: the circumcircle of ΔABC intersects diagonal BD at D.
Statement 2: the circumcircle of ΔABC intersects BD at D′inside the quadrilateral.
Statement 3: the circumcircle of ΔABC intersects BD at D′ outside the quadrilateral.
Statement 4: the circumcircle of ΔABCdoes not intersect BD at all.
Statement 5: ABCD is called cyclic quadrilateral.
Statement 1 and statement 5 are true
One of the statement 2 or statement 3 can be true
Only statement 4 is true
Only statement 1 is true