Visualising Formula for Mode Graphically
Trending Questions
Q.
How can we find mode if two classes have the highest and same frequency? How can we identify the median class if two classes are equally near to n2?
Q.
How f1 is calculated in mode?
Q.
The mode of a frequency distribution can be determined graphically from ________.
Histrogram
Frequency polygon
Ogive
Frequency curve
Q.
The mode of a frequency distribution is obtained graphically from
(a) a frequency curve (b) a frequency polygon
(c) a histogram (d) an ogive
Q. The mode of a frequency distribution can be determined graphically from
(a) Histogram
(b) Frequency polygon
(c) Ogive
(d) Frequency curve
(a) Histogram
(b) Frequency polygon
(c) Ogive
(d) Frequency curve
Q. The class mark of the modal class is
- 45
- 55
- 35
- 25
Q.
Mode=?
(a)xk+h.{(fk−1−fk)(2fk−fk−1−fk+1)} (b) xk+h.{(fk−fk−1)(2fk−fk−1−fk+1)}(c) xk+h.{(fk−fk−1)(fk−2fk−1−fk+1)} (d) xk+h.{(fk−fk−1)(fk−fk−1−2fk+1)}
Q. The modal class is the class that has the lowest frequency.
- False
- True
Q. The modal class is the class that has the lowest frequency.
- False
- True
Q. The following is the frequency distribution of blood pressure of 100 patients.
(i) Draw a less-than cumulative frequency curve and find the reading below which blood pressure readings of 50% patients were observed.
(ii) Draw the histogram and hence, find the approximate mode .
Blood pressure (in suitable units ) | 110-115 | 115-120 | 120-125 | 125-130 | 130-135 |
No. of patients | 2 | 35 | 52 | 8 | 3 |
(i) Draw a less-than cumulative frequency curve and find the reading below which blood pressure readings of 50% patients were observed.
(ii) Draw the histogram and hence, find the approximate mode .