Angular Analogue of Linear Momentum
Trending Questions
- constant linear momentum
- zero torque
- constant torque
- constant force
- 0.12 J-s
- 12 J-s
- 1.2 J-s
- 1.1.2 J-s
A particle of mass 'm' is projected with velocity 'v' making an angle of 45∘ with the horizontal. The magnitude of the angular momentum of the projectile about the point of projection when the particle is at its maximum height 'h' is
- mv34g
- mv3√2g
- m√2gh3
- Zero
- ω02
- ω04
- ω0
- ω03
uniform circular disc of mass 200 g and radius 4.0 cm is rotated about one of its diameter at an angular speed of 10 rad/s. Find the angular momentum about the axis of rotation
4 × 10−4 J−s
8 × 10−4 J−s
4 × 10−8 J−s
8 × 10−8 J−s
A particle of mass m is projected with velocity v making an angle of 45∘ with the horizontal. Themagnitude of the angular momentum of the particle about the point of projection when the particle is at its maximum height is (where g = acceleration due to gravity)
Zero
mv22g
mv3(4√2g)
mv3(√2g)
- √Iω2−mv2I
- √(I+mR2)ω2−mv2I
- Iω−mvRI
- (I+mR2)ω−mvRI
- Angular velocity
- Angular momentum
- Moment of Inertia
- Angular acceleration
A particle is projected at time t = 0 from a point P with a speed v0 at an angle of 45∘ to the horizontal. Find the magnitude and the direction of the angular momentum of the particle about the point P at time t = v0g
mv202√2g(−^k)
mv302√2g(−^k)
mv202√2g(^k)
mv302√2g(^k)
A particle 'm' starts with zero velocity along a line y = 4d. (Where d is a constant). The position of particle 'm' varies as x = A sin ωt. At ωt = π2, its angular momentum with respect to the origin is?
mAωd
mωdA
mAdω
zero
A cord is wound a round the circumfererence of a wheel of mass 50Kg and diameter 0.3m. The axis of the wheel is horizonatal. A mass of 0.5Kg is attached at the end of the cord. Find the angular acceleration of the wheel?
1.1rad/s2
1.2rad/s2
1.3rad/s2
1.4rad/s2
A particle is projected at time t =0 from a point P with a speed v0 at an angle of 45∘ to the horizontal. Find the magnitude and the direction of the angular momentum of the particle about the point P at time t =v0g.
mv302√2g^j
mv302√2g^(−j)
mv30√2g^j
2mv303^(−j)
A uniform rod of mass 'm' and Length 'L' is rotated about its perpendicular bisector at an angular speed ω. Calculate its angular momentum about its Axis of rotation?
ML212ω
32ML23ω
2ML212ω
ML224ω
- MEO
- HEO
- LEO
- Polar orbit
- Iv
- Iω
- Mω
- Iα
A small ball 'A' of mass 'm' is attached rigidly to the end of a light rod of length 'd'. The structure rotates about an axis perpendicular to the rod and passing through its other end with an angular velocity 'ω'. Calculate the angular momentum of the system about this axis?
- 14mωd2
- mωd2
- 12mωd2
- 2mωd2
0.003083 kgm2
0.004083 kgm2
0.002083 kgm2
- 0.001083 kgm2