Lens Formula
Trending Questions
Find the power of a concave lens of focal length 2 m.
- Position of image = 60 cm, image is virtual and erect
- Position of image = - 60 cm, image is virtual and erect
- Position of image = 60 cm, image is real and inverted
- Position of image = 12 cm, image is real and inverted
An object is placed 20 cm in front of a concave mirror of focal length 12 cm. Find the position and nature of the image.
A small object is so placed in front of a convex lens of 5cm focal length that a virtual image is formed at a distance of 25 cm . Find the magnification
An object is placed at a distance of 20 cm in front of a concave lens of focal length 20 cm. Find :
(a) the position of image, and
(b) the magnification of image.
What is the power of a combination of lenses?
Question 35
The image of a candle flame formed by a lens is obtained on a screen placed on the other side of the lens. If the image is three times the size of the flame and the distance between lens and image is 80 cm, at what distance should the candle be placed from the lens? What is the nature of the image at a distance of 80 cm and the lens?
To form an image twice the size of the object, using a convex lens of focal length 20 cm, the object distance must be
< 20 cm
> 20 cm
< 20 cm and between 20 cm and 40 cm
equal to 20 cm
- Focal length of the lens is 0.4 cm.
- Focal length of the lens is 40 cm.
- The lens is a converging lens.
- The lens is a diverging lens
An object of is placed at a distance of from a concave mirror of focal length . Find the position, nature and height of the image.
Why focal length of convex mirror and convex lens is positive while concave mirror and concave lens negative?
- Position of the image is 15 cm
- Position of the image is 60 cm
- Height of the image is 8 cm
- Height of the image is -8 cm
With respect to air, the refractive indices of water and benzene are and respectively. Calculate the refractive index of benzene with respect to water.
1) the focal length of lens
2) the magnification.
A concave lens forms the image of an object kept at a distance 20 cm in front of it, at a distance 10 cm on the side of the object. (a) What is the nature of the image ? (b) Find the focal length of the lens.
F - (A + E)- 2F
- A + B + C + D + E
F
The critical angle for glass is . The corresponding angle of refraction is:
lesser than but more than
no angle of refraction
An object is placed at 30 cm in front of the convex lens of focal length 10 cm. Find out the image distance from lens?
– 10 cm
+ 20 cm
+ 15 cm
– 20 cm
(a) Power of each lens
(b) Power of resulted lens
(c) Nature of resulted lens
(d) Focal length of the resulted lens
[5 MARKS]
An object is placed in front of a converging lens at a distance greater than twice the focal length of the lens. The image obtained is:
Real and inverted; magnified
Virtual and upright; magnified
Real and inverted; diminished
Virtual and upright; diminished
A point-like object is placed at a distance of in front of a convex lens of the focal length of. A plane mirror is placed at a distance of behind the lens. The position and nature of the final image formed by the system are:
from the mirror, virtual
from the mirror, virtual
from the mirror, real
from the mirror, real
13. An object is placed in front of a concave mirror having focal length . The object height is . Determine the location and size of image?
What is the magnification of the object? [4 MARKS]
Focal length of a convex lens is . Its power is
An object of the height of 2 cm is placed perpendicular to the principal axis of a concave lens of the focal length of 12 cm. find the height of the image, if the object is placed at a distance of 8 cm from the lens?