Mirror Equations and Focal Length
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In order to produce an image with magnification m, a concave mirror of focal length f is used. If the object is kept at a distance d from the mirror, then equals
- 8 cm behind the mirror
- 10 cm behind the mirror
- 8 cm in front of the mirror
- 10 cm in front of the mirror
Find out the image position formed by concave mirror, considering the image formed by plane mirror as an object for concave mirror.
30 cm, from the pole
40 cm, from the pole
60 cm, from the pole
20 cm, from the pole
- +½
- -½
- +1
- -1
- Infinity
- 15 cm infront of the mirror
- 15 cm behind the mirror
- 20 cm infront of the mirror
- -9.6 cm
- -8.3 cm
- -6.3 cm
- -3.6 cm
A 5.0 cm tall light bulb has placed a distance of 50 cm from a convex mirror having a focal length of 10 cm. What is the image height?
6/5 cm
-6/5 cm
-5/6 cm
5/6 cm
If AB is an object, CD is an image formed. If AP is object distance CP is image distance from the mirror. Then choose the correct sign convention.
1. height of image = + ve 2. height of image = – ve
3. height of object = + ve 4. height of object = – ve
5. AP = + ve 6. AP = – ve
7. PC = + ve 8. PC = – ve.
concave mirror – 1, 3, 5 & 7, plane mirror – 1, 3, 5, 7
concave mirror – 2, 3, 6 & 8, plane mirror – 1, 3 , 6 , 7
concave mirror – 2, 3, 6 & 8, plane mirror – 1, 3, 6, 8
concave mirror – 2, 3, 5, 7, plane mirror – 1, 3, 6,
A 1 cm tall light bulb is placed at a distance of 50 cm from a convex mirror having a focal length of 10 cm. The height of the image is:
6/5 cm
-6/5 cm
-5/6 cm
5/6 cm
- 6 cm
- - 6 cm
- 30 cm
- - 30 cm
The focal length of the convex lens is 20 cm and focal length of the concave mirror is 30 cm. And the separation between lens and mirror is 90 cm. If the object is placed 60 cm before the lens, find out the position of the image formed by the concave mirror.
60 cm left of lens
60 cm from point B
60 cm from point A
90 cm from point B
A point object is placed at a distance of 30 cm from a convex mirror of focal length 30 cm. The image will form at
infinity
15 cm infront of the mirror
20 cm infront of the mirror
15 cm behind the mirror
- 10 m s−1
- 20 m s−1
- 5 m s−1
- 2.5 m s−1
- 40 cm, 10 cm
- 40 cm, 5 cm
- 20 cm, 20 cm
- 20 cm, 10 cm
- 15 cm, 30 cm
- 30 cm, 15 cm
- 30 cm, 60 cm
- 60 cm, 30 cm
- 2
- 1.5
- 1
- 2.5
- 8.5 cm
- 30 cm
- 90 cm
- 60 cm
- v= –20 cm
- v= +30 cm
- v= +20 cm
- v= –30 cm
An object is placed at 60 m in front of a concave mirror. If its radius of curvature is 20 m, then the image distance is equal to
- 15 cm, 30 cm
- 30 cm, 15 cm
- 30 cm, 60 cm
- 60 cm, 30 cm
An object is placed at a distance of 10 cmfrom a concave mirror of radius of curvature 0.6 m. Which of the following statement is incorrect?
The image is formed at a distance of 15 cm from the mirror.
The image formed is real.
The image is 1.5 times the size of the object.
The image formed is virtual and erect.