Characteristics of Equilibrium Constant
Trending Questions
Q. A nitrogen-hydrogen mixture initially in the molar ratio of 1:3 reached equilibrium to from ammonia when 25% of the N2 and H2 had reacted .If the pressure of the system was 21 atm , the partial pressure of ammonia at the equilibrium was
Q. Statement 1: The value of the equilibrium constant, K, depends on the temperature at which the reaction is happening.
Statement 2: A Catalyst is a substance which can change the speed of the chemical reaction without itself getting consumed
Statement 2: A Catalyst is a substance which can change the speed of the chemical reaction without itself getting consumed
- TT
- TF
- FT
- FF
Q. For the hypothetical reactions, the equilibrium constant (K) values are given:
A⇌B; K1=2B⇌C; K2=4C⇌D;K3=3
The equilibrium constant for the reaction A⇌D will be:
A⇌B; K1=2B⇌C; K2=4C⇌D;K3=3
The equilibrium constant for the reaction A⇌D will be:
- 48
- 6
- 24
- 12
Q. In the chemical reaction A+B→AB; B is acting as a limiting reagent then choose the correct option.
AIIMS-MBBS-2019-26 May-Morning Q.80
AIIMS-MBBS-2019-26 May-Morning Q.80
- A = 50 atm, B = 100 atm
- A = 100 atm, B = 200 atm
- A = 50 atm, B = 200 atm
- A = 50 atm, B = 30 atm
Q.
The equilibrium constant for the reaction,
CaCO3(s) ⇌ CaO(s) + CO2 (g), is
Q. A reversible chemical reaction having two reactants in equilibrium. If the concentration of the reactants are doubled, then the equilibrium constant will:
- Also be doubled
- Be halved
- Become one-fourth
- Remain the same
Q. 22. Why there is opposite effect of pressure changes when del n is negative and positive according to Le chatlier principle?
Q. In an alkaline solution, the following equilibria exist.
S2−+S→S2−2equilibrium constant K1
S2−2+S→S2−3 equilibrium constant K2
K1 and K2 have the values 12 and 11, respectively.
S2−3→S2−+2S. What is equilibrium constant for the reaction?
S2−+S→S2−2equilibrium constant K1
S2−2+S→S2−3 equilibrium constant K2
K1 and K2 have the values 12 and 11, respectively.
S2−3→S2−+2S. What is equilibrium constant for the reaction?
- 132
- 7.58×10−3
- 1.09
- 0.198
Q. For the following gaseous equilibria X, Y and Z at 300 K
X: 2SO2+O2⇌2SO3
Y: PCl5⇌PCl3+Cl2
Z: 2HI⇌H2+I2
The ratio of Kp and Kc in the increasing order will be:
X: 2SO2+O2⇌2SO3
Y: PCl5⇌PCl3+Cl2
Z: 2HI⇌H2+I2
The ratio of Kp and Kc in the increasing order will be:
- X = Y = Z
- X < Y < Z
- X < Z < Y
- Z < Y < X
Q. At 87oC, the following equilibrium is established:
H2(g)+S(s)⇌H2S(g), Kc=8×10−2
If 0.3 mole of hydrogen and 2 mole of sulphur are heated to 87oC in a 2 L vessel, what will be the partial pressure of H2S at equilibrium.
H2(g)+S(s)⇌H2S(g), Kc=8×10−2
If 0.3 mole of hydrogen and 2 mole of sulphur are heated to 87oC in a 2 L vessel, what will be the partial pressure of H2S at equilibrium.
- 0.32 atm
- 1.43 atm
- 0.62 atm
- 4.0 atm
Q. When NO and NO2 are mixed, the following equilibria are readily obtained :
2NO2⇌N2O4 Kp=6.8 atm−1
and
NO+NO2⇌N2O3
In an experiment when NO and NO2 are mixed in the ratio of 1:2, the final total pressure was 5.05 atm and the partial pressure of N2O4 was 1.7 atm. Calculate the equilibrium partial pressure of NO in atmosphere :
2NO2⇌N2O4 Kp=6.8 atm−1
and
NO+NO2⇌N2O3
In an experiment when NO and NO2 are mixed in the ratio of 1:2, the final total pressure was 5.05 atm and the partial pressure of N2O4 was 1.7 atm. Calculate the equilibrium partial pressure of NO in atmosphere :
- 1.05 atm
- 4 atm
- 6 atm
- 8 atm
Q. The equilibrium constant Kc or Kp for endothermic reaction increases with
- Increase in temperature
- Decreases in temperature
- No effect of temperature
- Increases in pressure
Q. Under a given set of experimental conditions , with increase in the concentration of the reactants , the rate of a chemical reaction.
- Decreases
- Increases
- Remains unaltered
- First decreases and then increases
Q. N2+3H2⇌2NH3, starting with one mole of nitrogen and 3 moles of hydrogen, at equilibrium 50% of each had reacted. If the equilibrium pressure is P, the partial pressure of hydrogen at equilibrium would be:
- P2
- P3
- P4
- P6
Q. Given:
N2 (g)+3H2 (g)⇌2NH3 (g); K1
N2 (g)+O2 (g)⇌2NO (g); K2
H2 (g)+12O2 (g)⇌H2O (g); K3
where K1, K2, K3 are equilibrium constants.
The equilibrium constant for the reaction,
2NH3 (g)+52O2 (g)⇌2NO (g)+3H2O (g) will be:
N2 (g)+3H2 (g)⇌2NH3 (g); K1
N2 (g)+O2 (g)⇌2NO (g); K2
H2 (g)+12O2 (g)⇌H2O (g); K3
where K1, K2, K3 are equilibrium constants.
The equilibrium constant for the reaction,
2NH3 (g)+52O2 (g)⇌2NO (g)+3H2O (g) will be:
- K1K2K3
- K1K2K3
- K1K23K2
- K2K33K1
Q. Consider the general hypothetical reaction:
A(s)⇋2B(g)+3C(g)
If the concentration of C at equilibrium is doubled, then after the equilibrium is re-established, the concentration of B will be :
A(s)⇋2B(g)+3C(g)
If the concentration of C at equilibrium is doubled, then after the equilibrium is re-established, the concentration of B will be :
- Twice of its original value
- Half of its original value
- 2√2 times of original value
- 12√2 times the original value
Q. Which one of the following statements is not correct?
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Q.
What indicator should be used (in terms of its pKin)for the titration of 0.10 M KH2BO3 with 0.10 M HCl ?
pKin = 2.2
pKin = 5.22
pKin = 9.56
pKin = 6.6
Q. For an equilibrium reaction, the rate constants for the forward and backward reactions are 2.38×10−4s−1 and 8.15×10−5s−1 respectively. The equilibrium constant for the reaction is:
- 0.342
- 2.92
- 0.292
- 3.42
Q. C(s)+O2(g)−→ CO2(g)ΔH∘=−393.5 kJ mol−1
C(s)+12O2(g)−→ CO(g)ΔH∘=−110.5 kJ mol−1
H2(g)+12O2(g)−→ H2O(g)ΔH∘=−241.8 kJ mol−1
The standard enthalpy change ( in kJ mol−1) for the reaction.
CO2(g)+H2(g)⟶CO(g)+H2O(g) is
C(s)+12O2(g)−→ CO(g)ΔH∘=−110.5 kJ mol−1
H2(g)+12O2(g)−→ H2O(g)ΔH∘=−241.8 kJ mol−1
The standard enthalpy change ( in kJ mol−1) for the reaction.
CO2(g)+H2(g)⟶CO(g)+H2O(g) is
- −262.2
- +41.2
- −41.2
- +262.2
Q. A vessel; at 1000 K contains CO2 with a pressure of 0.5 atm. Some of the CO2 is converted into CO on the addition of graphite. If the total pressure at equilibrium is 0.8 atm, the value of K is:
- 1.8 atm
- 3 atm
- 0.3 atm
- 0.18 atm
Q. For the chemical equilibrium, CaCO3(s)⇌CaO(s)+CO2(g), △Ho, can be determined from which one of the following plots
Q. Two solid compounds X and Y dissociates at a certain temperature as follows
X(S)⇌A(g)+2B(g);KP1=9×10−3 atm3
Y(s)⇌2B(g)+C(g); KP2=4.5×10−3 atm3
The total pressure (in atm) of gases over a mixture of X and Y is :
X(S)⇌A(g)+2B(g);KP1=9×10−3 atm3
Y(s)⇌2B(g)+C(g); KP2=4.5×10−3 atm3
The total pressure (in atm) of gases over a mixture of X and Y is :
Q. What is Kc for the following equilibrium when the equilibrium concentration of each substance is: [SO2]=0.60M, |O2|=0.82M and [SO3]=1.90M ?
2SO2(g)+O2(g)⇌2SO3(g)
2SO2(g)+O2(g)⇌2SO3(g)
Q. The degree of dissociation of SO3 is α at equilibrium pressure P. KP for SO3(g)⇌SO2(g)+12O2(g)
- P2α22(1−α)3
- P12α3/2(1−α)(2+α)1/2
- P2α22(1−α)2
- None of these
Q. Match the following.
ReactionDegree of dissociation in terms of(Homogeneous gaseous phase)equilibrium constant(a)A(g)+B(g)⇌2C(g)(p)(√K)/(1+√K)(b)2A(g)⇌B(g)+C(g)(q)(√K)/(2+√K)(c)A(g)+B(g)⇌C(g)+D(g)(r)2K/(1+2K)(d)AB(g)⇌A2(g)+B2(g)(s)2√K1+2√K(t) K
ReactionDegree of dissociation in terms of(Homogeneous gaseous phase)equilibrium constant(a)A(g)+B(g)⇌2C(g)(p)(√K)/(1+√K)(b)2A(g)⇌B(g)+C(g)(q)(√K)/(2+√K)(c)A(g)+B(g)⇌C(g)+D(g)(r)2K/(1+2K)(d)AB(g)⇌A2(g)+B2(g)(s)2√K1+2√K(t) K
- a–q, b–s, c−p, d−r
- a–q, b–p, c−s, d−r
- a–r, b–s, c−p, d−q
- a–s, b–p, c−r, d−q
Q.
[[Q]]
Calculate a) G°and b) the equilibrium constant for the formation of NO2 from NO and O2 at 298 K
where fG° (NO2) = 52.0 kJ/mol
fG° (NO) = 87.0 kJ/mol
fG° (O2) = 0 kJ/mol