Conductivity of Ionic Solutions
Trending Questions
Q.
The equivalent conductance at infinite dilution of a weak acid such as HF
Can be determined by measurement of very dilute HF solution
Is an undefined quantity
Can be determined by extrapolation of measurements on dilute solutions
of HCl, HBr and HI
Can best be determined from measurements on dilute solutions of
NaF, NaCl and HCl
Q. (CH3)3NO and (CH3)3PO dipole moment comparison with reason.
Q. In a disproprtionation reaction addition of 2 equations : 10e + 5Cl2 --- 10Cl^-1 and Cl2 --- 2ClO3^-1 + 10e cancelled 10e How?? As the elections have neg. charge on them.
Q. The specific conductance of an acid HA of 0.1 M concentration is 3.75×10−4Ω−1cm−1. If λ∞(HA)=250Ω−1cm2mol−1. The dissociation constant Ka of HA is y×10−5. Find the value of y
Q. The equivalent conductivity of a 0.01 N solution of a monobasic acid is 70.0 S cm2eq−1. If the equivalent conductivity of the acid at infinite dilution is 350 Scm2eq−1. Then
- The degree of dissociation of the acid is 20 %
- The dissociation constant of the acid is 5.0×10−4
- The osmotic pressure of the solution is 22.4 cm of Hg at 300K
- The pH of the solution is 2.7
Q.
Electrolyte can conduct electricity because
Their molecules contain unpaired electrons, which are mobile
Their molecules contain loosely held electrons which get free under the influence of voltage
The molecules break up into ions when a voltage is applied
The molecules are broken up into ions when the electrolyte is fused or is dissolved in the solvent
Q. The equivalent conductivity of a 0.01 N solution of a monobasic acid is 70.0 S cm2eq−1. If the equivalent conductivity of the acid at infinite dilution is 350 Scm2eq−1. Then
- The degree of dissociation of the acid is 20 %
- The dissociation constant of the acid is 5.0×10−4
- The osmotic pressure of the solution is 22.4 cm of Hg at 300K
- The pH of the solution is 2.7
