Derivation of Kp and Kc
Trending Questions
The mole of each component PCl5, PCl3 and Cl2 at equilibrium were found to be 2. If the total pressure is 3 atm. The value of KP will be-
- 1 atm
- 2 atm
- 3 atm
- 1.5 atm
CaCO3 (s)⇌ CaO (s)+CO2 (g)
- Kc=[CaO]×[CO2][CaCO3]
- Kc=[CO2]2[CaCO3]
- Kc=[CO2]
- None of the above
2SO2+O2⇌2SO3
- 12.24 M−1
- 1.23 M−1
- 22.23 M−1
- 32.23 M−1
PCl5(g)⇌PCl3(g)+Cl2(g)
- 0.625 atm
- 4 atm
- 1.6 atm
- None of these
- -27.1
- -19.6
- 1.1
- 27.1
The equilibrium constant in a reversible reaction at a given temperature
It is not characteristic of the reaction
Depends on the concentration of the products at equilibrium
Depends on the initial concentration of the reactants
Does not depend on the initial concentrations
For the reaction CaCO3(s) ⇋ CaO(s) + CO2(g) the partial pressure of CO2 (at equilibrium) depends on:
the mass of CaO
the mass of CaCO3
Both a and b
temperature
- 27x216V2(a−x)
- 27x416V2(a−x)2
- 27x416V4(a−x)2
- 27x216V2(a−x)2
- 0.266
- 0.53
- 2.66
- 5.3
During the kinetic study of the reaction, give following results were obtained.
Run | in | in | Initial rate of formation of in |
1 | 0.1 | 0.1 | |
2 | 0.3 | 0.2 | |
3 | 0.3 | 0.4 | |
4 | 0.4 | 0.1 |
On the basis of the above data which one is correct?
- 50.08 atm−1
- 10.08 atm−1
- 50.07 atm−1
- None of the above
In the reversible reaction A + B ⇌ C + D, the concentration of each C and D at
equilibrium was 0.8 mole/litre, then the equilibrium constant KC will be
6.4
0.64
1.6
16.0
[I2(g) ⇋ 2 I(g)]. Kp for the equilibrium will be
- 0.67
- 1.5
- 2.67 × 104
- 9.0 × 104
Given: PCl5⇌PCl3+Cl2
- 5
- 4
- 8
- 1
A⇌B;K1=2;B⇌C;K2=4;C⇌D;K3=3
The equilibrium constant (K) for the reaction A⇌D is:
- 48
- 6
- 24
- 12
- 37.04 atm2
- 22.52 atm2
- 18.52 atm2
- 45.04 atm2
Consider the following equilibrium in a closed container:
N2O4 (g) ⇋ 2NO2 (g)
At a fixed temperature, the volume of the reaction container is halved. For this change, which of the following statements holds true regarding the equilibrium constant Kp and degree of dissociation α?
neither Kp nor α changes
both Kp and α changes
Kpchanges, but α does not change
Kp does not change, but α changes
CO(g)+H2O(g)⇌CO2(g)+H2(g)
△Ho300 K=−41.16 kJ mol−1
△So300 K=−4.24×10−2 kJ mol−1
Calculate Kp (at 300 K.)
- 4.93×104
- 8.93×10−4
- 8.93×104
- None of the above
- 33.33%
- 75%
- 50%
- 15%
N2(g)+3H2(g)⇌2NH3(g)
- 1.677×10−3 atm−2
- 2.677×10−3 atm−2
- 0.677×10−3 atm−2
- 3.677×10−3 atm−2
4NH3(g)+5O2(g)⇌4NO(g)+6H2O(g)
- Kp=[PNO]4[PH2O]6[PNH3]4[PO2]5
- Kp=[PNH3]4[PO2]5[PNO]4[PH2O]6
- Kp=[PNH3][PO2][PNO][PH2O]
- Kp=[PNO][PH2O][PNH3][PO2]
2HI(g)⇌H2(g)+I2(g)
SO2Cl2 (g)⇋ SO2 (g) + Cl2 (g) is 2.9x 10−2~atm. If the total pressure is 1 atm, the degree of dissociation of SO2Cl2 is (assume 1−α2 =1)
- 85%
- 12%
- 17%
- 35%
The thermal decomposition of N2O4g) ⇋ 2NO2 (g) is as shown below:
N2O4(g)⇌2NO2(g)At starta mol 0 molAt equb.(a−x)mol 2x mol
Where x = degree of dissociation. If V and P are equilibrium volume and pressure respectively then the corresponding expressions for Kc and Kp are 4x2V(a−x) and 4x2a2−x2 (respectively). True or False?
True
False
A (g)+B (g)⇌2 C (g)
The equilibrium concentration of A and B each is 0.2 mol L−1 and concentration of C is observed as 0.60 mol L−1 Equilibrium constant Kc will be :
- 9
- 18
- 6
- 24
2 moles of PCl5 were heated in a closed vessel of 2 litre capacity. At
equilibrium, 40% of PCl5 is dissociated into PCl3 and Cl2. The value of
equilibrium constant is
0.53
2.66
0.266
5.3
N2O4(g)⇌2NO2(g)
is attained at 25oC. The total equilibrium pressure in container is 380 torr. If equilibrium constant of above equilibrium is 0.667 atm, then degree of dissociation of N2O4 at this temperature will be:
- 13
- 12
- 23
- 14