Effect on Kc
Trending Questions
What is the relation between ∆H and ∆U?
∆H = ∆U - RT
∆H = ∆U + RT
∆H = ∆U + ∆nRT
∆H = ∆U
H2 + I2 = 2HI In the above equilibrium system if the concentration of the
reactants at 25∘Cis increased, the value of KC will
Increase
Decrease
Remains the same
Depends on the nature of the reactants
Regarding the rate of a reversible reaction, the correct explanation of the effect
of catalyst is
It decreases the velocity of backward reaction
It provides a new reaction path of low activation energy
It increases the kinetic energy of reacting molecules
It displaces the equilibrium state on right side
The equilibrium constant Kp of the reaction, 2SO2(g) + O2(g) \(\leftrightharpoons\) 2SO3(g) is 900 atm. at 800 K. A mixture containing SO3and O2 having initial pressure of 1 and 2 atm respectively is heated at constant volume to equilibrate. Calculate the partial pressure of SO2 gas at 800 K.
0.0236 atm
0.05 atm
1.03 atm
0.442 atm
For the reaction N2(g)+3H2(g)⇌2NH3(g), ΔH=−93.6 kJ mol−1. The amount (i.e. number of mole) of~H2 at equilibrium will
increase if
Volume is increased
Volume is decreased
is added at constant volume
is removed.
Fe(s)+Zn2+(aq)⇌Zn(s)+Fe2+(aq)
What will be the value of log[Fe2+] at equilibrium when a piece of iron is placed in a 1 M of Zn2+ solution?
- +5.42
- −10.83
- −5.42
- +10.83
Regarding the rate of a reversible reaction, the correct explanation of the effect
of catalyst is
It provides a new reaction path of low activation energy
It increases the kinetic energy of reacting molecules
It displaces the equilibrium state on right side
It decreases the velocity of backward reaction
- total pressure
- catalyst
- the amounts of H2 and I2 present
- temperature
Initial concentration of A is equal to that of B. The equilibrium concentration of A and C are equal. Kc of the reaction will be:
- 0.08
- 0.8
- 8
- 80
NH4HS(s)⇌NH3(g)+H2S(g), is followed to set-up at 127 ∘C in a closed vessel. The total pressure at equilibrium was 20 atm. The Kc for the reaction is:
(Given R=0.08 L atm K−1 mol−1)
- 0.097 M2
- 0.085 M2
- 3.045 M2
- 1.04 M2
Dissociation constants for AOH and BOH are 1.1×10−8 and 1.7×10−9 respectively.(Report the answer upto second decimal)
- 6 L
- 9 L
- 36 L
- None of these
- produce more I−(aq)
- drive it to the right
- produce more H2
- not affect the system