Ellingham Diagram
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- Electrolysis
- Thermal reduction
- Vapour phase refining
- Zone refining
- Electrolysis
- Thermal reduction
- Vapour phase refining
- Zone refining
- 3Mn3O4+8Al→9Mn+4Al2O3
- Cr2O3+2Al→Al2O3+2Cr
- 2Fe+Al2O3→2Al+Fe2O3
- 3TiO2(s) +4Al(s) → 2Al2O3 (s) +3Ti(l)
In the Ellingham diagram for oxides, the general trend for the graphs for metal to metal oxide is
They slope upwards
They are all parallel to the ΔG∘ = 0 horizontal axis
There is no common trend
They slope downwards like the 2C+O2 → 2CO line
For the following question, the answer is an integer between 0 and 9 (both inclusive).
In the Ellingham diagram for oxides, there are x lines for the reaction(s) between C and O. What is x?
The ΔfG∘T line for C+O2 → CO2 is nearly parallel to the ΔfG∘ = 0 – True or False?
True
False
You are given an Ellingham diagram (deliberately not shown). It is given that for almost all practically achievable temperatures, the Fe→Fe2O3 line lies above the Al→Al2O3 line and ΔfG∘ for both Al2O3 and Fe2O3 are negative. Which of the following statements is/are true?
Under the given conditions, neither metal can reduce the other oxide
Fe can reduce Al2O3 into Al
Al can reduce Fe2O3 into Fe
Both b and c
- In the decomposition of a metal oxide into oxygen and solid metal, entropy increases
- Decomposition of an oxide is an endothermic change
ΔG° vs T graph for the formation of CO2 has negative slope- ΔG° vs T graph for the formation of CO has negative slope.
You are given an Ellingham diagram (deliberately not shown). It is given that for almost all practically achievable temperatures, the Fe→Fe2O3 line lies above the Al→Al2O3 line and ΔfG∘ for both Al2O3 and Fe2O3 are negative. Which of the following statements is/are true?
Under the given conditions, neither metal can reduce the other oxide
Fe can reduce Al2O3 into Al
Al can reduce Fe2O3 into Fe
Both b and c
- oxides
- halides
- sulphides
- all of these