Enthalpy of Neutralisation
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- + 1.9 kJ
- - 1.9 kJ
- 3.8 kJ
- - 3.8 kJ
The enthalpy of neutralization of HCl and NaOH is −57 kJ mol−1. The heat evolved at constant pressure (in kJ) when 0.5 mole of H2SO4 react with 0.75 mole of NaOH is equal to
57 x 3/4
57 x 0.5
57
57 x 0.25
Sodium hydroxide is neutralised by hydrochloric acid
Ammonium hydroxide is neutralised by hydrochloric acid
Sodium hydroxide is neutralised by acetic acid
Ammoniym hydroxide is neutralised by acetic acid
At a particular temperature H+(aq) + OH−(aq) → H2O(l); ΔH = −57.1kJ. The approximate heat evolved when 400 mL of 0.2 H2SO4 is mixed with 600 mL of 0.1 m KOH solution will be:
3.42kJ
13.7 kJ
5.2kJ
55kJ
- More than x
- Equal to x
- Less than x
- Twice that of x
At a particular temperature H+(aq) + OH−(aq) → H2O(l); ΔH = −57.1kJ. The approximate heat evolved when 400 mL of 0.2 H2SO4 is mixed with 600 mL of 0.1 m KOH solution will be:
3.426kJ
13.7kJ
5.2 kJ
55kJ
- 500 x
- 100 x
- x
- 10 x
31. In permutit process, what is the role of addition of the concentrated solution of solid compound obtained due to the reaction between NaOH and HCl.
13.7 kcal
57 kJ
5.7×104 J
All of the above
The enthalpy of neutralization of HCl and NaOH is −57 kJ mol−1. The heat evolved at constant pressure (in kJ) when 0.5 mole of H2SO4 react with 0.75 mole of NaOH is equal to
57 × 34
57 × 0.5
57
57 × 0.25
- NH4OH and CH3OOH
- NH4OH and HCl
- NaOH and CH3OOH
- NaOH and HCl
Calculate △Hionization of H3PO3 into its ions:
- 50.84 kJ/mol
- 5 kJ/mol
- 2.5 kJ/mol
- None of these
Column - IColumn - II(Enthalpy change in kcal)(Neutralisation)(A)<13.7kcal(p)HCl(1mol)+NaOH(1mol)(B)=13.7kcal(q)HF(1mol)+NaOH(1mol)(C)>13.7kcal(r)NH4OH(1mol)+HCl(1mol)(D)=27.4kcal(s)NaOH(2mol)+H2SO4(1mol)(t)NaOH(1mol)+CH3COOH(1mol)
- a - r, t
b - p
c - q, s
d - s - a - r, t, s
b - p
c - q,
d - s - a - r, t, s
b - p, s
c - q, s
d - s - a - r, t
b - p, s
c - q, s
d - p
Calculate △Hionization of H3PO3 into its ions:
- 50.84 kJ/mol
- 5 kJ/mol
- 2.5 kJ/mol
- None of these
- 6.4 cal
- 9.4 cal
- 3.5 cal
- 1.4 cal
- -43.8 kJ
- 43.8 kJ
- 68 kJ
- -68 kJ
Given : density and specific heat of solution is 1g mL−1 and 4.2 Jg−1 ∘C−1
- −50.4 kJ/mol
- −54.4 kJ/mol
- −57.7 kJ/mol
- −63.2 kJ/mol
x = 2y
x = 3y
x = 4y
- x = 12 y
- 20 mL acid and 30 mL alkali
- 10 mL acid and 10 mL alkali
- 35 mL add and 15 mL alkali
- 50 mL acid and 50 mL alkali
- 1.5%
- 3.57%
- 35.7%
- 10%
- Sodium hydroxide is neutralised by acetic acid
- Ammoniym hydroxide is neutralised by acetic acid
- Ammonium hydroxide is neutralised by hydrochloric acid
- Sodium hydroxide is neutralised by hydrochloric acid
- 57.1 kJ/eq.
- 5.71 kJ/eq.
- 0.571 kJ/eq.
- 571 kJ/eq.
- A
- B
- C
- D
The enthalpy of neutralization of HCl and NaOH is −57 kJ mol−1. The heat evolved at constant pressure (in kJ) when 0.5 mole of H2SO4 react with 0.75 mole of NaOH is equal to
57 × 34
57 × 0.5
57
57 × 0.25