Factors Affecting Alpha
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Electrolytes when dissolved in water dissociate into their constituent ions.
The degree of dissociation of an electrolyte increases with
Increasing concentration of the electrolyte
Decreasing concentration of the electrolyte
Decreasing temperature
Presence of a substance yielding a common ion
NaOH is a strong base because
It gives OH− ion.
It can be oxidised
It can be easily ionised
It provides H3O+ ions.
How many gram moles of HCl will be required to prepare one litre of a buffer solution (containing NaCN and HCN) of pH 8.5 using 0.01 gram formula weight of NaCN ?
Ka (HCN) = 4.1 × 10−10
The extent of ionization increases
With the increase in concentration of solute
On addition of excess water to solution
On decreasing the temperature of solution
On stirring the solution vigorously
In the purification of NaCl, impure solution is saturated with HCl gas. The principle involved is
Common ion effect and low solubility of MgCl2 and CaCl2 when compared to NaCl
Common ion effect and high solubility of MgCl2 and CaCl2 when compared to NaCl
KSP of NaCl is greater than that of MgCl2
KSP of NaCl is greter than that of CaCl2 but less than that of MgCl2
C = 0.2 M
- 1.6×10−4
- 1.8×10−5
- 2×10−4
- 1.7×10−5
Ammonium hydroxide is a weak base because
It has low vapour pressure
It is only slightly ionized
It is not a hydroxide of any metal
It has low density
- 2×10−7 M
- 1×10−6 M
- 3×10−5 M
- 1×10−4 M
Electrolytes when dissolved in water dissociate into their constituent ions.
The degree of dissociation of an electrolyte increases with
Increasing concentration of the electrolyte
Decreasing concentration of the electrolyte
Decreasing temperature
Presence of a substance yielding a common ion
- 0.084 atm
- 0.84 atm
- 0.42 atm
- 0.042 atm
- 1.5×10−6 M
- 9×10−3 M
- 1.8×10−4 M
- 6.8×10−5 M
An ionizing solvent has
Low value of dielectric constant
High value of dielectric constant
A dielectric constant equal to 1
Has a high melting point
0.1 mole of CH3NH2(Kb=5 × 10−4 is mixed with 0.08 mole of HCl and
diluted to one litre. What will be the H+ concentration in the solution?
8 x 10-2 M
8 x 10-11 M
1.6 x 10-11 M
8 x 10-5 M
- 0.5×10−3
- 2.62×10−6
- 4.2×10−6
- 1.27×10−4
- 2.5×10−3
- 2.5×10−4
- 5×10−3
- 5×10−4
- At 298K , Equilibrium constant of water < ionic product of water
i.e. Kc<Kw - Kw at 373 K >Kw at 298 K
- Ionic product of water at 25∘C is 10−14
- None of the above.
- 2×10−7 M
- 1×10−6 M
- 3×10−5 M
- 1×10−4 M
- 1.41×10−5 M
- 7.07×10−10 M
- 9.5×10−12 M
- 4×10−6 M
(Ka=1.6×10−4)
- 4×10−3 M
- 3×10−6 M
- 1.5×10−3 M
- 5×10−6 M
- 4×10−4 M
- 16×10−4 M
- 81×10−4 M
- 9×10−4 M
define common ion effect. how does it effect the solubility of electrolytes.
(A)→When water is heated to 80∘ C then concentrations [H+] and [OH−] will increase.
Reason:
(R)→Kw increases with decrease in temperature.
- Both, A and R, are true and R is the correct explanation of A
- Both, A and R, are true but R is not the correct explanation of A
- A is true but R is false
- Both A and R are false
What is the value of pX of 0.1 M H3A(aq) solution?
Given pX=−logX and X=[A3−][HA2−].
- 7
- 8
- 9
- 10
Select the correct statement from the following:
- The concentration of CO2−3 is 0.034 M.
- The concentration of CO2−3 is greater than that of HCO−3.
- The concentration of H+ and HCO−3 are approximately equal.
- The concentration of H+ is double that of CO2−3.
where,
α1 is the degree of dissociation of HOCl
α2 is the degree of dissociation of CH3COOH
Given that:
Ka1(HOCl)=2×10−7
Ka1(CH3COOH)=2×10−5
- 0.2
- 0.02
- 0.01
- 0.5
Given that,
Kb(AOH)=1×10−8
Kb(BOH)=2×10−9
- 1.16×10−5 M
- 6×10−8 M
- 4.55×10−3 M
- 3×10−8 M
Find the concentration of S2− and HS− ions (in mol/L) respectively in the solution consisting of 0.1 M H2S and 0.5 M HCl.
- 5.2×10−21 and 2×10−8
- 1.0×10−18 and 2.3×10−6
- 6.5×10−19 and 1.3×10−7
- 4.6×10−20 and 1.3×10−8