Fruendlich Isotherm

Q. A plot of log $\frac{x}{m}$ versus log P for the adsorption of a gas on a solid gives a straight line with slope equal to:

1. n
2. $\frac{1}{n}$
   
3. log K
4. - log K

Q. Which of the following graphs represents the Freundlich adsorption isotherm correctly?

1. 
2. 
3. 
4. 

Q. Adsorption of a gas follows the Freundlich adsorption isotherm. 'x' is the mass of the gas adsorbed on mass 'm' of the adsorbent. The plot of $log\frac{x}{m}$ versus $logp$ is shown in the graph given below, $\frac{x}{m}$ is proportional to:

1. $p^{\frac{2}{3}}$
2. $p^2$
3. $p^3$
4. $p^{\frac{3}{2}}$

Q. I, II and III are three adsorption isotherms at three temperatures $T_1$, $T_2$ and $T_3$, where $x$ is the amount of adsorbate adsorbed per $mg$ of the adsorbent.
The temperatures $T_1$, $T_2$ and $T_3$ are in the order

1. $T_1<T_2<T_3$
2. $T_1=T_2=T_3$
3. $T_3<T_2<T_1$
4. No specific order

Q. In the adsorption of a gas on solid, Freundlich isotherm is obeyed. Thus, if the slope of the plot is zero, then the extent of adsorption is:

1. directly proportional to the pressure of gas
2. inversely proportional to the pressure of the gas
3. independent of the pressure of the gas
4. proportional to the square of the pressure of the gas

Q. A plot of log $\frac{x}{m}$ versus log P for the adsorption of a gas on a solid gives a straight line with slope equal to:

1. n
2. $\frac{1}{n}$
   
3. log K
4. - log K

Q. Adsorption of a gas follows Freundlich adsorption isotherm
$x$ is the mass of the gas adsorbed on mass $m$ of the adsorbent. $P$ is the pressure of the gas

In the plot of ${\log }_e\left(\frac{x}{m}\right)$ vs ${\log }_{e}P$:
Here
$m=\text{slope}c=\text{Intercept}$

Q.

Plot of log x/m against log P is a straight line inclined at an angle of ${45}^{\circ }$. When the pressure is 0.5 atm and Freundlich parameter. K is 100, the amount of the solute adsorbed per gram of adsorbent will be (log 5 = 0.6990)

1. 1 g

2. 2 g

3. 3 g

4. 5 g

Q. Which is not true about the Freundlich adsorption isotherm curve?

1. At low pressures, the value of $n=1$
2. From the $ln\frac{x}{m}$ vs $P$ curve, we can find the value of n by finding the slope
3. At higher pressures, the value of $\frac{x}{m}$ is almost constant
4. At a fixed pressure, there is a decrease in physical adsorption with increase in temperature

Q. The equation for Freundlich adsorption isotherm is

a) $\frac{x}{m}=k{p}^{\frac{1}{n}}$
b) $\left(lnx\right)=ln\left(mk\right)+\frac{1}{n}lnp$
c) $\frac{x}{m}=k{p}^{-n}$
d) Only a and b

1. a
2. b
3. c
4. d