Gibb's Energy and Nernst Equation
Trending Questions
- −322 kJ mol−1
- −161 kJ mol−1
- −152 kJ mol−1
- 76 kJ mol−1
- ΔG° = 7.18 kJ, ΔH° = −14.42 kJ
- ΔG° = −7.18 kJ, ΔH° = 57.50 J
- ΔG° = −7.18 kJ, ΔH° = −14.42 kJ
- ΔS° = −24.125 JK−1, reaction is spontaneous
(JEE MAIN 2021
2H++12O2+2e−→2H2O, E∘=+1.23V,
Fe2++2e−→Fe(s); E∘=−0.44V.
ΔG∘ (in kJ) for the reaction is :
- - 76
- -322
- -122
- -176
The electrical work done during the reaction at 298 K:
2Hg(l)+Cl2(g)→Hg2Cl2(s), isGiven that E∘Cl2Cl−=1.36V;E∘Hg2Cl2Hg, Cl−=0.27V;PCl2=1 atm,
210.37 kJ mol−1
105.185 kJ mol−1
420.74 kJ mol−1
110.37 kJ mol−1
On the basis of information available from the reaction:
43Al+O2→23Al2O3ΔG=−827 KJ/mol of O2. The minimum e.m.f. required to carry out
electrolysis of Al2O3 is
2.14V
4.28V
6.42V
8.56V
- 463 K
- 35440 K
- 20 K
- 483 K
The standard electrode potentials, K+/K= -2.93V, Ag+/Ag = 0.80V, the electrode which is negatively charged is
Ag+/Ag
K+/K
Any of the two
None of them
A voltaic cell has an E° value of (–1V). The cell reaction:
is spontaneous
has a positive ΔG°
has a negative ΔG°
has K = 1
The value of ΔG(kJmol−1) for the given cell is: (take1F=96500 C mol−1)
- −5.7
- 5.7
- 11.4
- −11.4
Zn(s)|ZnSO4(aq)||CuSO4(aq))|Cu(s)
When the concentration of Zn2+ is 10 times the concentration of Cu2+, the expression for ΔG (inJmol−1) is
[F is Faraday constant; R Is gas constant; T is temperature ; E∘(cell)=1.1v]
- 2.303 RT + 1.1 F
- 1.1 F
- 2.303 RT - 2.2 F
- -2.2 F
Pt(s)|H2(g, 1 bar)|H+(aq, 1M)||M4+(aq), M2+(aq)|Pt(s)Ecell=0.092 V when [M2+(aq)][M4+(aq)]=10xGiven:E0M4+/M2+=0.151 V;2.303RTF=0.059 V
The value of x is:
- -2
- -1
- 1
- 2
The electrical work done during the reaction at 298 K:
2Hg(l)+Cl2(g)→Hg2Cl2(s), isGiven that E∘Cl2Cl−=1.36V;E∘Hg2Cl2Hg, Cl−=0.27V;PCl2=1 atm,
210.37 kJ mol−1
105.185 kJ mol−1
420.74 kJ mol−1
110.37 kJ mol−1
- ΔG° = 7.18 kJ, ΔH° = −14.42 kJ
- ΔG° = −7.18 kJ, ΔH° = 57.50 J
- ΔG° = −7.18 kJ, ΔH° = −14.42 kJ
- ΔS° = −24.125 JK−1, reaction is spontaneous
Pt(s)|H2(g, 1 bar)|H+(aq, 1M)||M4+(aq), M2+(aq)|Pt(s)Ecell=0.092 V when [M2+(aq)][M4+(aq)]=10xGiven:E0M4+/M2+=0.151 V;2.303RTF=0.059 V
The value of x is:
- -2
- -1
- 1
- 2
K+/K = -2.93 V, Ag+/Ag = +0.80 V, Cr+3/Cr = -0.74 V
Out of these electrode which will be the strongest reducing agent?
- EX+EY
- E0X+E0Y
- -(ΔG0X + ΔG0Y)/nF
- ΔG0X + ΔG0Y
Given standard electrode potentials
Fe+++2e−→Fe; E∘=−0.440 V
Fe++++3e−→Fe; E∘=−0.036 V
The standard electrode potential (E∘) for Fe++++e−→Fe++ is
- 0.476 V
- 0.404 V
+ 0.404 V
+ 0.772 V
- E∘cell>0, ΔG∘<0
- E∘cell<0, ΔG∘>0
- E∘cell>0, ΔG∘>0
- E∘cell=0, ΔG∘=0
The value of ΔG(kJmol−1) for the given cell is: (take1F=96500 C mol−1)
- −5.7
- 5.7
- 11.4
- −11.4
- - 98430 J
- 98430 J
- 96500 J
- - 49215 J