Haloacids

Q. Which reaction can't be used for the preparation of the given halogen acid?

1. $2KBr+H_{2}S{O}_4\left(conc\right)⟶K_{2}S{O}_4+2HBr$
2. $2NaCl+H_{2}S{O}_4\left(conc\right)⟶N{a}_{2}S{O}_4+2HCl$
3. $NaHS{O}_4+NaCl⟶N{a}_{2}S{O}_4+HCl$
4. $Ca{F}_2+H_{2}S{O}_4\left(conc\right)⟶CaS{O}_4+2HF$

Q. $HBr$ and $HI$ reduce sulphuric acid, $HCl$ can reduce $KMn{O}_4$ and $HF$ can reduce :

1. $H_{2}S{O}_4$
2. $KMn{O}_4$
3. $K_{2}C{r}_2{O}_7$
4. None of the above

Q. $HF$ is liquid at room temperature and $HCl$ is as gas at room temperature because H-bonding is present in $HF$.

1. False
2. True

Q. HBr and HI reduce sulphuric acid, HCl can reduce $KMn{O}_4$ and HF can reduce

1. $KMn{O}_4$
2. None of the above
3. $H_{2}S{O}_4$
4. $K_{2}C{r}_2{O}_7$

Q. HF is weak acid in comparison to HBr, HCl and HI due to

1. Weak van der Waals force
2. Hydrogen bonding
3. Back bonding
4. High electronegativity of ‘F’

Q.

Which of the following hydracids is the strongest acid?

1. HCl

2. HF

3. HBr

4. HI

Q. Given below are two statements :
Statement I : $H_2{O}_2$ can act as both oxidising and reducing agent in basic medium.
Statement II : In the hydrogen economy, the energy is transmitted in the form of dihydrogen.

In the light of the above statements, choose the correct answer from the options given below :

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1. Both statement I and statement II are true
2. Both statement I and statement II are false
3. Statement I is true but statement II is false
4. Statement I is false but statement II is true

Q. $HF$ is liquid at room temperature and $HCl$ is as gas at room temperature because H-bonding is present in $HF$.

1. False
2. True