Heat of Reaction
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The enthalpy change for a given reaction at 298 K is −x J mol−1 (x being positive). If the reaction occurs spontaneously at 298 K, the entropy change at that temperature
Can be negative but numerically larger than x/298
Can be negative but numerically smaller than x/298
Cannot be negative
Cannot be positive
- -13.09 kcal
- -18.69 kcal
- 13.09 kcal
- 18.69 kcal
- Van't Hoff equation
- Clausius-Clapeyron equation
- Nernst equation
- Kirchoff's equation
- 57.1 kJ
- 14.3 kJ
- 28.55 kJ
- None
150 calories
50 calories
-50 calories
-150 calories
Consider the following data:
ΔfH0 (N2H4, l) = 50 kJ/mol
ΔfH0 (NH3, g) = −46k J/mol
B.E.(N−H) = 393 kJ/mol and B.E.(H−H) = 436 kJ/mol, also ΔvapH(N2H4, l) = 18 kJ/mol
The N- N bond energy in N2H4 is
45.45 kJ/mol
190 kJ/mol
226 kJ/mol
154 kJ/mol
Fe2O3(s)+3H2(g) → 2Fe(s)+3H2O(l)
Given that , ΔH298=−33.29 kJ mol−1 and CP for Fe2O3(s), Fe(s), H2O(l) and H2(g) are 103.8, 25.1, 75.3, and 28.8 J/K mol.
- −28.136 kJ/mol
- −58.136 kJ/mol
- 28.136 kJ/mol
- 58.136 kJ/mol
For H2O(l) (1bar, 373K) → H2O(g) (1bar, 373K).The correct set of thermodynamic parameter is
∆G = 0, ∆S = + ve
∆G = 0, ∆S = -ve
∆G = + ve, ∆S = 0
∆G = - ve, ∆S = + ve
- H of the product is less than that H of reactants
where H is the enthalpy of the product or reactant - H of the product is more than that H of reactants
where H is the enthalpy of the product or reactant - H of the product is equal to the H of reactants
where H is the enthalpy of the product or reactant - ΔH=ΔH(products)−ΔH(reactants) is always positive
P4(s)+5O2(g)→P4O10(s) ΔH=−3013 kJ/mol
- 60226 kJ
- 12052 kJ
- 1252 kJ
- 3052 kJ
- 1.40
- 1.70
- 1.50
- 1.33
- 29.4 kJ
- – 11.8 kJ
- – 29.4 kJ
- + 11.8 kJ
(g)C2H4 + 3O2(g) ⟶2CO2(g) + 2H2O(g) is called:
Enthalpy of formation
Enthalpy of sublimation
Enthalpy of combustion
Enthalpy of vaporization