Introduction to Oxidation and Reduction
Trending Questions
Q.
In an Alkaline medium reacts as follows: . Find the Equivalent weight of
Q. The order of increasing Oxidation number of S in S8, S2O2−8, S2O2−3, S4O2−6 is:
- S8<S2O2−8<S2O2−3<S4O2−6
- S2O2−8<S2O2−3<S4O2−6<S8
- S2O2−8<S8<S4O2−6<S2O2−3
- S8<S2O2−3<S4O2−6<S2O2−8
Q. The value of x in the partial redox equation
MnO−4+8H++xe=Mn2++4H2O is
MnO−4+8H++xe=Mn2++4H2O is
5
3
1
0
Q. Equivalent mass of KMnO4 in acidic, basic and neutral are in the ratio of :
(Given, molecular mass of KMnO4=158 g)
(Given, molecular mass of KMnO4=158 g)
- 3:5:15
- 5:3:1
- 5:1:3
- 3:15:5
Q. In basic medium, CrO2−4 oxidize S2O2−3 to form SO2−4 and itself changes to Cr(OH)−4. How many mL of 0.154 M CrO2−4 are required to react with 40 mL of 0.246 M S2O2−3 ?
- 200 mL
- 156.4 mL
- 170.4 mL
- 190.4 mL
Q. For a cell involving one electron Eocell=0.59 V at 298 K, the equilibrium constant for cell reaction is :
[Given that 2.303 RTF=0.059V at T=298 K]
(NEET-2019)
[Given that 2.303 RTF=0.059V at T=298 K]
(NEET-2019)
- 1.0×102
- 1.0×105
- 1.0×1030
- 1.0×1010
Q. 12 g of Mg will react completely with a monoprotic acid to give:
- 5 moles of H2
- 1 mole of acid
- 1/2 mole of H2
- 1 mole of O2
Q. 100 ml of each of 0.5NNaOH, N5HCl and N10H2SO4 are mixed together. The resulting solution will be
- Acidic
- Neutral
- Alkaline
- None
Q. In the reaction NaOH+H3PO4→Na2HPO4+H2O, the equivalent weight of H3PO4 (phosphoric acid) is:
- 98
- 49
- 32.66
- 24.5
Q. What is the sum of oxidation numbers of oxygen and hydrogen in O2 and H2 respectively?
- −1
- 0
- Can't be predicted
- +2
Q. Calculate the weight of Na2CO3 of 85% purity required to prepare to neutralize 45.6 mL of 0.235 N H2SO4 ?
- 2.05 g
- 1.44 g
- 0.25 g
- 0.67 g