Nature of Oxides
Trending Questions
The compound which could not act both as oxidising as well as reducing agent is
MnO2
SO2
Al203
CrO
- True
- False
- True
- False
- +12
- −12
- +1
- All of the above
The formation of the oxide ion, O2−(g) from oxygen atom requires first an exothermic and then an endothermic step as shown below:
O(g)+e−→O−(g);ΔfH∘=−141 kJ mol−1O−(g)+e−→O2−(g);ΔfH∘=+780 kJ mol−1
Thus, process of formation of O2− in gas phase is unfavourable even though O2− is isoelectronic with neon. It is due to the fact that,
O− ion has comparatively smaller size than oxygen atom.
oxygen is more electronegative
addition of electron in oxygen results in larger size of the ion.
electron repulsion outweighs the stability gained by achieving noble gas configuration.
- Chemical formula of anion is O−2
- They are also called hyperoxide
- Both (A) and (B)
- None of these
- O−2
- O−
- O−3
- All of the above
Metallic nature and basic nature of the oxides ........ as we move along a period
Remains constant
Decreases
First increases then decreases
Increases
- O−2
- O−
- O−3
- All of the above
- Sodium
- Phosporous
- Carbon
- Sulphur
in the above ruels to ditermine the oxidation No. the second point states
The oxidation number of a monoatomic ion is equal to the charge of the ion. For example, Mg2+ has oxidation number +2; Clā has oxidation number ā1.
here Mg2+ is not a monoatomic ion ?