Oxidising and Reducing Nature
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- CO
- SnO
- PbO
- GeO
- CI4
- GeI4
- SnI4
- PbI4
Read the following and select one the correct answer.
Statement I: Pb4+ compounds are stronger oxidizing agents than Sn2+ compounds
Statement II: The higher oxidation states for the group 14 elements are more stable for the heavier members of the group due to inert pair effect.
Statement I and Statement II are both correct. Statement II correctly explains Statement I
Statement I and Statement II are both correct. Statement II does not explain Statement I
Statement II is correct and Statement I is wrong
- Statement I is correct and Statement II is wrong
- because I− get oxidised to I2
- because I− is a strong reducing agent
- because I2 is a gas
- because I− is a strong oxidising agent
It is because of the inability of ns2 electrons of the valence shell to participate in bonding that
Sn2+ is oxidizing while Pb2+ is reducing
Sn2+ and Pb2+ are both oxidizing and reducing
Sn4+ is reducing while Pb4+is oxidizing
Sn2+ is reducing while Pb4+is oxidizing
- Pb is more electropositive than Ge
- Ionization potential of lead is less than that of Ge
- Ionic radii of Pb2+ and Pb4+are larger than those of Ge2+ and Ge4+
- Lead is heavier than Germanium
- because I− get oxidised to I2
- because I− is a strong reducing agent
- because I2 is a gas
- because I− is a strong oxidising agent
- They have the same number of protons
- They have valence electrons with the same quantum numbers
- They have the same number of neutrons
- They have the same number of electrons
- They have similar outer-shell electron configurations