Radioactive Series

Q. The element ${}_{90}^{232}Th$ belongs to 4n series which will be the end product of this series:

1. ${}_{83}^{209}Bi$
2. ${}_{82}^{208}Bi$
3. ${}_{82}^{209}Bi$
4. ${}_{82}^{207}Bi$

Q. The end product of $(4n+2)$ radioactive disintegration series is

1. ${}_{82}P{b}^{208}$
2. ${}_{82}P{b}^{206}$
3. ${}_{82}P{b}^{207}$
4. ${}_{83}B{i}^{210}$

Q. The end product of $(4n+2)$ radioactive disintegration series is

1. ${}_{82}P{b}^{208}$
2. ${}_{82}P{b}^{206}$
3. ${}_{82}P{b}^{207}$
4. ${}_{83}B{i}^{210}$

Q. Radioactivity of naptunium stops when it is converted to

1. Bi
2. Rn
3. Th
4. Pb