Reductions Involving Aldehydes or Ketones
Trending Questions
Q. 23 Potassium dichromate reacts with potassium iodide in acidic medium what is the oxidation state of product formed from reductant A. +1 B. Zero C. +3 D. +5
Q. Acetophenone is reduced by LiAlH4 to
- Toluene
- Ethyl benzene
- 1-Phenylethanol
- Phenol
Q. 71. How many sigma bond π bond lone pair are present in P4O10 and P4O6
Q. Ratio of number of o (sigma) and Tt(pi-) bondspresent in the molecule C2(CN)4 is(1) 1 1(2)21(3) 1 2(4) 3 2
Q.
The C-H bond distance is longest in:
C6H6
C2H2
C2H4Br2
C2H4
Q. which of the following bonds had highest bond energy
1.H-H Bond in H2
2.C-C bond in C2H6
3.N-N bond N2H4
4.O-O bond in H2O2
Q. 29. Calculate no of sigma bonds pie bonds lone pairin the following molecules 1 xeO2F2 2 H2so4 3 H3po4
Q. 32. How to calculate bond order and bond length in CN, CO , NH3+
Q. The appropriate reagent for the following transformation is :
- Zn(Hg), HCl
- NH2−NH2, OH⊝
- H2Ni
- NaBH4
Q. How many cyclic isomers of c6h10 having no double bond?
Q. which of the following has maximum value of Ka2?
(a)HOOC-COOH (b)HOOC-CH2-COOH (c)HOOC-(CH2)2-COOH (d)HOOC-(CH2)3-COOH
Q. In the Rosenmund's reduction, BaSO4 taken with catalyst Pd acts as
Promotor
Catalytic poison
- Cooperator
- Absorber
Q. Benzene reacts with CH3COCl in the presence of anhydrous AlCl3 to give
Q.
1‑propanol & 2‑propanol can be best distinguished by:
- Oxidation with alkaline \(KMnO_4\) followed by reaction with Fehling solution
- Oxidation with acedic dichromate followed by reaction with Fehling solution
- Oxidation by heating with copper followed by reaction with Fehling solution
- Oxidation with concentrated \(H_2SO_4\) followed by reaction with Fehling
Q. 15.Why hybridised orbitals cannot form pi bond but can form sigma bonds ?
Q.
Which of the following will have highest number of no bond resonating structures?
CH2 = CH2
(CH3)2 – C = C(CH3)2
CH3 – CH = CH2
Q. Which of the following bonds has the highest bond energy?why?(1) S-S(2) O-O(3) Se-Se(4) Te-Te
Q. What is the stability order of single, double and triple bonds?
Single>double>triple?
As sigma bonds are stronger than pi bonds?
Q. Predict the products of electrolysis in each of the following.
A dilute solution of H2SO4 with platinum electrodes.
Q. A: iodine is a mild oxidising agent R: iodine can be used for treating sodium thiosulphate 1) both assertion and reason are true and the reason is the correct explanation of the assertion. 2) both assertion and reason are true but the reason is not the correct explanation of the assertion. 3) assertion is true statement but reason is false 4) both assertion and reason are false statements.
Q.
For conversion of nitrile into aldehyde reagent A will be:
For conversion of nitrile into aldehyde reagent A will be:
- SOCl2, H3O+
- DIBAL−H, H3O+
- RLi, H3O+
- RMgX, H3O+
Q. Hydrogenation of benzoyl chloride in the presence of Pd and BaSO4 gives
- Benzyl alcohol
- Benzaldehyde
- Benzoic acid
- Phenol
Q.
Which of the following is a comproportionation reaction ?
None of these
Q. CocCl_{2(aq) +} H_2O_{2_{(aq)}}\xrightarrow[{basic medium}]{}Co(OH)_{3(s)}+C{l^-}_{(aq)} Balance rthe redox equation by oxidation niumber method
Q. Complete the following chemical reaction and classify into (a) hydrolysis, (b) redox and (c) hydration reactions.
Ca3N2(s)+H2O(l)→
Q.
The products (a) and (b) are :
The products (a) and (b) are :
Q. Methyl - ethyl ketone can be reduced to n-butane using the reaction:
- MPV reduction
- Wolf Kishner reduction
- Mg−Hg, H2O
- All the above
Q. But-2-enal on reduction with hydro borane (9-BBN) gives
- But-1-ene
- Butane
- But-2-en-1-ol
- Butanal
Q. Given below are two reactions.
Choose the possible products.
Choose the possible products.
- product B is diphenylmethanol
- Product A is 1-phenylcyclohexan-1-ol
- Product A is 2-phenylcyclohexan-1-ol
- None of the above
Q. Hydrogenation of benzoyl chloride in the presence of Pd and BaSO4 gives
- Benzyl alcohol
- Benzaldehyde
- Benzoic acid
- Phenol