Root Mean Square Velocity
Trending Questions
Q. Which of the following options is/are correct with respect to CH4 and SO2? (Equal mass of CH4 and SO2 are contained in a 2 L container at same temperature)
- CH4 will diffuse 4 times faster than SO2
- Average speed of CH4 is 2 times that of SO2
- Both have the same average kinetic energy per mol
- CH4 has double the partial pressure of SO2
Q. The root mean square speed of molecules of nitrogen gas is v at a certain temperature. When the temperature is doubled, the molecules dissociate into individual atoms. The new rms speed of the atom is:
- √2v
- 2v
- v
- 4v
Q. At 298 K, which of the following gases has the lowest average molecular speed ?
- CH4 at 0.80 atm
- He at 0.40 atm
- CO2 at 0.20 atm
- NO at 1.00 atm
Q. For CO2, given that average velocity at T1 is equal to most probable velocity at T2. Thus, T1T2
- 2.26
- 1.27
- 0.78
- 1.13
Q. The root mean square speed of 8 g of He is 300 ms−1. Total kinetic energy of He gas is:
- 120 J
- 240 J
- 360 J
- None of these
Q.
The R.M.S. velocity of hydrogen is √7 times the R.M.S. velocity of Nitrogen. If T is the temperature of the Gas, then
Q. The mass of molecule A is twice that of molecule B. The root mean square velocity of molecule A is twice that of molecule B. If two containers of equal volume have same number of molecules, the ratio of pressure PAPB will be:
- 8 : 1
- 1 : 8
- 4 : 1
- 1 : 4
Q.
The R.M.S. velocity of hydrogen is √7 times the R.M.S. velocity of Nitrogen. If T is the temperature of the Gas, then
TH2=TN2
TH2>TN2
TH2<TN2
TH2=√7×TN2
Q.
The R.M.S. velocity of hydrogen is √7 times the R.M.S. velocity of Nitrogen. If T is the temperature of the Gas, then
TH2=TN2
TH2>TN2
TH2<TN2
TH2=√7×TN2
Q. The ratio of the root mean square speed of H2 gas at 50 K and that of O2 gas at 800 K is:
- 4
- 2
- 1
- 0.25
Q. For gaseous state, if most probable speed is denoted by C*, average speed by →C and root mean square speed by C, then for a large number of molecules, the ratios of these speeds are
- C* : ¯C : C = 1.225 : 1.128 : 1
- C* : ¯C : C = 1.128 : 1.225 : 1
- C* : ¯C : C = 1 : 1.128 : 1.225
- C* : ¯C : C = 1 : 1.225 : 1.128
Q. Let, the average molar mass of air is 24.9 g. An open vessel at 27 oC is heated upto t oC until 1/3rd of the air measured at final temperature excapes out. The rms velocity of air molecules at t oC is: (Take R=8.3 JK−1mol−1)
- 340.12 m sec−1
- 420.35 m sec−1
- 515.25 m sec−1
- 632.45 m sec−1