Shapes of Orbitals and Nodes
Trending Questions
Q. The wave function for the 1s orbital of a hydrogen atom is given by:
Ψ1s=π√2e(−ra0)
where, a0 = Radius of first Bohr's orbit
r = Distance from the nucleus (probability of finding the electron varies with respect to it)
What will be the ratio of probabilities of finding the electron at the nucleus to the first Bohr's orbit at r=a0?
Ψ1s=π√2e(−ra0)
where, a0 = Radius of first Bohr's orbit
r = Distance from the nucleus (probability of finding the electron varies with respect to it)
What will be the ratio of probabilities of finding the electron at the nucleus to the first Bohr's orbit at r=a0?
- e
- e2
- 1e2
- Zero
Q. The number of radial nodes in 5d orbital is:
- 0
- 1
- 2
- 3
Q.
Which pair of quantum numbers determine the energy of an electron in an orbital?
n and l
n and m
n and ms
l and m
Q. The nodal plane(s) for dx2−y2 is/are:
- x−y=0
- x+y=0
- xy plane
- Both a and b
Q. Which of the following orbitals is non-directional?
- 3s
- 4f
- 4d
- 4p
Q. the most covalent halide is __ and why?a)AlF3 b)AlCl3 c)AlBr3 d) AlI3
Q. The number of nodal planes in the px orbital is/are:
- One
- Two
- Three
- Zero
Q. What is alpha, beta and Gama hydrogen atoms?
Q.
How Many Radial Nodes Are Present In Orbital ?
Q. why is probability density of finding electron maximum at nucleus although nodal plane passes through the centre?
Q. Statement - 1: The number of radial nodes in 3s and 4p orbitals are not equal.
Statement - 2: The number of radial nodes in 3s and 4p orbitals depend on ‘n′ and ‘l′ which are different for 3s and 4p orbital.
Statement - 2: The number of radial nodes in 3s and 4p orbitals depend on ‘n′ and ‘l′ which are different for 3s and 4p orbital.
- Statement-1 is True, Statement-2 is True, Statement-2 is the correct explanation for Statement-1.
- Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1.
- Statement-1 is True, Statement-2 is False.
- Statement-1 is False, Statement-2 is True
Q. 64 Structure of s2o8-2
Q. 32. Two hybrid orbitals have a bond angle of 120^° . the percentage of p character in the hybrid orbital is nearly
Q. Total number of radial nodes and angular nodes present in 7p orbitals are:
- 5 and 0
- 6 and 1
- 5 and 1
- 7 and 1
Q. the period of revolution of an electron in the 1st orbit to that of in the 2nd orbit of H atom is in the ratio of
Q. On which quantum numbers does the orbital angular momentum of an electron in a hydrogen-like atomic orbital depend?
Q. Which of the following orbitals does not have a planar node?
dz2
dxy
dyz
dx2−y2
Q. Plots for 2s orbitals are:
X, Y and Z are respectively
X, Y and Z are respectively
- ψ, ψ2, 4πψ2r2,
- ψ2, 4πψ2r2, ψ
- 4πψ2r2, ψ2, ψ
- ψ2, ψ, 4πψ2r2
Q.
The penetration power within a principal quantum number goes like
s> p > d > f
s < p < d < f
s > p < d < f
s < p > d > f
Q. Which of the following orbital has 2 radial as well as 2 angular nodes.
3s
<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}-->- 3d
- 4d
- 5d
Q. Number of nodal planes (planes of zero electron density) in the dxy orbital is:
- 1
- 2
- \N
- 4
Q. The nodal plane(s) for dx2−y2 is/are:
- x−y=0
- x+y=0
- xy plane
- Both a and b
Q. Which of the following statements is true regarding dz2 orbital?
- It is like a single dumbbell along the z axis, with a doughnut like ring around the nucleus on the x-y plane.
- It has no planar nodes
- It has two angular nodes
- All of the above
Q. 5.Why cant sigma Bond be formed between s-d orbitals or p-d orbitals or d-d orbitals?
Q.
A pi-bond is formed by the overlap of:
s-p orbitals
s-s orbitals
p-p orbitals in sidewise manner
p-p orbitals in end to end fashion
Q. The correct statement regarding the 4py orbital is:
- The number of maxima when a curve is plotted between 4πr2R2(r) vs r is 3
- Number of spherical nodes is 3
- xz plane acts as a nodal plane
- Magnetic quantum number must be −1
Q.
The H-like species Li2+ is in spherically symmetrical state S1 and one radial node. Upon absorbing light, the ion undergoes transition to state S2. The state S2 has one radial node and it has the same energy as the ground state energy of a hydrogen atom.
The orbital angular momentum quantum number of state S2 is:
- 0
- 1
- 2
- 3
Q. The wave function (Ψ) of 2s is given by:
Ψ2s=12√2π(1a0)12{2−ra0}e−r2a0
At r=r0, radial node is formed. Thus for 2s, r0 in terms of a0 is:
Ψ2s=12√2π(1a0)12{2−ra0}e−r2a0
At r=r0, radial node is formed. Thus for 2s, r0 in terms of a0 is:
- r0=a0
- r0=2a0
- r0=a02
- r0=4a0
Q. n = 3, l = 1, m = –2, s = –1/2 is it possible ? in electronic configuration\backslash
Q. Removal of electron is most difficult from which of the following orbital?