Zeff
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Q. three atoms P, Q, R andd crystallize in a cubic solid lattice where P atoms are the alternate faces, R atoms are the center of edges and Q atoms are at the 2/3 rd of the total corners present , hence the formula of the compound.
Q. 8. FeO crystallizes into a cubic structure and has edge length of 5.0 angstrom , the density is 4 gm/cm cube then the no of ferrous and oxide ions present in each unit is ? 1) 4 ferrous and 4 oxide 2) 2 ferrous and 2 oxide 3) 4 ferrous and 2 oxide 4) 2 ferrous and 4 oxide
Q. 26. A solid is made up of 2 elements X and Y . Atoms x are in fcc arrangement and y atoms occupy all the octahedral sites and atlernate tetrahedral sites . What is the formula of compound ?
Q. 37. An atomic solid A crystallizes in a body centre lattice and the inner surface of the atoms at the adjacent corner are separated by 60.3 pm. If the atomic weight of A is 48, then density of the solid is nearly :- (1) 2.7 g/cc (2) 5.07 g/cc (3) 3.5 g/cc (4) 1.75 g/cc
Q. an element occurs in BCC structure with edge length of 288pm the density of element is 7.2 how many atoms of the element does 208g of the eleme
Q. The sulphate of a metal M contains 9.87% of M.This sulphate is isomorphous with ZNSO4.7H2O.The atomic weight of M
Q. 10. A giant molecule contains 0.25% of a metal whose atomic weight is 59. Its molecule contains one atom of that metal. Its minimum molecular weight is - (1) 5900 (2) 23600 (3) 11800 (4) (100*59)/0.4
Q. 29. A compound formed by element X, Y, Z has a cubic structure in which X atom are at the corner of the cube and also at alternate face centre Y atom are present at the body center and Z atom are present at the alternate edge centre then the molecular formula of the compound is
Q. A compound is formed by elements X and Y, which has a cubic structure in which X atoms are at the corners and two Y atoms are at each body diagonal of the cube. If all atoms from one body diagonal of the cube except corners are removed, calculate- 1) Z_{eff} , 2) total number of atoms in the cube, 3) formula of the compound
Q. if the ratio of coordination no. of A to that of B is x:y, then the ratio of no. of atoms of A to that no. of atom B i unit cell i
Q. The density of a gaseous element is 5 times that of oxygen under similar conditions. If the molecule is triatomic, wht will be its atomic mass
Q. Ferrous oxide has a cubic structure and each edge of the unit cell is 5.0 angstrom. Assuming density of the oxide as 4.0 g/cm2, then find he number of Fe2+ and O2-ions present in each unit cell.
Q. A compound is formed by two elements p and q . if atom p are in ccp arrangement and atom q occupy 50% tv and 50% ov then formula of compound is
Q. one atom ofan element (E) weighs 4×10^{-23} g number of gram atoms in 240g of element (E) is approximately
Q. 74. Calculate the number of formula units of a crystal AB having CsCl type structure in 240gm. The unit cell edge length of AB is 200pm and density of the crystal is 6g/ cc ??
Q. 54. In NaCl crystal actual radius ratio is 0.525 if radius ofCi- ion is 250 pm, then the minibetween two Cl ions will be(1) 268 prm(3) 539 prm(2) 240 pm(4) 480 pm
Q. An element X (molar mass = 80 g/mol) having focstructure, calculate number of unit cells in 8 g of X.(1) 0.4× NA(2) 0.1 x N(3) 4 x N(4) 0, 025 × NA
Q. 30. A unit cell consists of a cube in which anions B are present at each corner and cations A at the centre of the alternate faces of the unit cell. What is the simplest formula of the compound? Also tell that how many atoms are there in alternate faces of a cube and atoms present at the centre of alternate daces of a cube with diagram.
Q. When heated above 916∘C, iron changes its bcc crystalline form to fcc without the change in the radius of atom. The ratio of density of the crystal before and after heating is:
Given:
[At. wt. of Fe=56 g mol−1]
Given:
[At. wt. of Fe=56 g mol−1]
- 1.57
- 0.91
- 1.73
- 0.25
Q. Antifluorite structure is derived from fluorite structure by
- None of these
- Subjecting fluorite structure to high pressure.
- Interchanging the positions of positive and negative ions in the lattice.
- Heating fluorite crystal lattice
Q. a compound has a molecular weight of 350.it contains 20% by mass of N2, then number of atoms of N2 in one molecule of the compound is
Q. An element (atomic mass =100gm/mol) having BCC structure has unit cell edge 400pm. The density of element is
Q. 38. An element (atomic mass =100gm) having bcc structure has unit cell edge 400 pm . The density of element is
Q. The density of a unit cell in (g/cm3) can be represented as :
Here,
a is the edge length in pm
Zeff is the effective number of particles in a unit cell
M is the molar mass NA is the avogadro number
Here,
a is the edge length in pm
Zeff is the effective number of particles in a unit cell
M is the molar mass NA is the avogadro number
- MNA×a3×10−30×Zeff
- Zeff×MNA×a3×10−30
- NA×a3×10−30Zeff×M
- NA×a3×10−30×ZeffM
Q. Why does ClO³ dimerises but ClO² doesnt??
Q. 18. How many number of atoms are present in hexagonal close packing unit cell A)4 B)6 C)12 D)17
Q. Sodium metal crystallizes in a body centred cubic lattice with a unit cell edge of 4.29 Å. The radius of sodium atom is approximately.
(AIEEE 2015)
(AIEEE 2015)
- 1.86 Å
- 0.93 Å
- 5.72 Å
- 3.22 Å
Q. Taking the reference to be the corner particles for a fcc lattice, the number of second nearest atoms and the distance between them is, respectively :
Here,
r is the radius of the atom
Here,
r is the radius of the atom
- 8 and 4r√2
- 8 and 4r√3
- 6 and 4r√2
- 12 and 4r√3
Q. Which of the following is the correct order of dipole moment?
H20
View SolutionQ. Given that density of NaCl is nearly 2×103 kg m−3 and molecular weight is 58.5×10−3 kg mol−1. Then calculate the value of a3 for unit cell of sodium chloride.
Here a is edge length of the fcc unit cell.
Take NA=6×1023
Here a is edge length of the fcc unit cell.
Take NA=6×1023
- 4.44×10−29 m3
- 1.95×10−28 m3
- 0.4×10−30 m3
- 3.5×10−27 m3