Relations Between Roots and Coefficients
Trending Questions
Let be a quadratic polynomial such that . If one of the roots of is , then its other roots lies in
Factorize the following:
- c2(mn)=ab(m+n)2
- b2(m+n)=mn
- mnb2=ac(m+n)2
- m+n=b2mn
If a+b=5, ab=2, then \(a^{3} +b^{3}=\)
If the roots of the equations x2−bx+c=0 and x2−cx+b=0 differ by the same quantity, then b+c is equal to
4
0
1
-4
If the roots of the equation 6 x2 -5x + k = 0 are in the ratio 2:3, then k
- x2+2x−24=0
- x2+2x+24=0
- x2−2x+24=0
- x2−2x−24=0
If α, β are the roots of the equation 4x2+3x+7=0, then find the value of α2β+β2α
(−16)21
1621
2116
(−21)16
- 1
- −1
- 2
- 3
If the ratio of the roots of the equation x2+px+q=0 be equal to the ratio of the roots of x2+lx+m=0. Then
pm2 = q2 l
p2 l = q2 m
p2m = l2 q
p2 m = q2 l
If one root of 5x2+13x+k=0 is reciprocal of the other, then k is equal to :
16
5
0
6
- 94(9−q2)
- 94(9+p2)
- 94(9+q2)
- 94(9−p2)
- x2−5x+84=0
- x2+5x−84=0
- x2−5x−84=0
- x2+5x+84=0
- −1, 0
- −1, 1
- −2, 1
- 0, 1
If tan α, tan β are the roots of the equation x2 + ax + b = 0 then the value of sin2(α+β)+a sin(α+β)cos(α+β)+b cos2(α+β)=
a
1a+b
ab
b
- ad2=b2c
- bd2=a2c
- b2d=ac2
- a2d=bc2
- x2−x−42=0
- x2+x+42=0
- x2−x+42=0
- x2−x+21=0
- 5
- 7
- 3
- 6
If one root of the quadratic equation ax2+bx+c=0 is equal to the nth power of the other root. Then the value of (acn)1n+1+(anc)1n+1
−b
b
−b1n+1
b1n+1
The coefficient of x in the quadratic equation x2+px+q=0 was taken as −14 in place of −10, its roots were found to be 6, 4. If α, β are the roots of correct equation, then the value of α2+β2 must be equal to
- −283375
- −6723375
- 6723375
- 283375
If tan A, tan B are the roots of x2−Px+Q=0 the value of sin2 (A+B)=(where P, Q ϵ R)
P2P2+Q2
P2(P+Q)2
P2P2+(1−Q)2
Q2P2+(1−Q)2
- a=c
- b=c
- a+c=0
- a+b=0
If ∝, β are the roots of the equation x2−ax+b=0, then α4+α3β+α2β2+αβ3+β4
None of these
a3+3a2b + b2
a4+3a2b + b2
a4−3a2b + b2
If k1, k2, k3 are real numbers and the equation k1x2+k2x+k3=0 have three roots, then value of k1+k2+k3 is
1
3
0
2
- pqr
- pq
- qr
- pr
If the ratio of the roots of the equation ax2+bx+c=0 be p:q, then
pqb2−(p+q)2ac=0
pqa2−(p+q)2bc=0
pqb2+(p+q)2ac=0
pqb2−(p−q)2ac=0
- a(1x)2+b(1x)+cx=0
- (ax)2+(bx)+c=0
- None of the above
- a(1x)2+b(1x)+c=0