AM,GM,HM Inequality
Trending Questions
A man has 7 friends. In how many ways he can invite one or more of them for a tea party.
128
127
256
130
For a polynomial with real coefficients, let denote the number of distinct real roots of . Suppose is the set of polynomials with real coefficients defined by
For a polynomial , let and denote its first and second order derivatives, respectively.
Then the minimum possible value of , where , is _____
If the arithmetic, geometric and harmonic means between two positive real numbers be and , then
- s<t and a101>b101
- s<t and a101<b101
- s>t and a101<b101
- s>t and a101>b101
limx→0(e1/x−1)(e1/x)+1
1
0
-1
Does not exist
If x be real, then the minimum value of x2−8x+17 is
2
-1
0
1
Differentiate xex using first principle.
Prove that the following statement is true : If x, y∈Z such that x and y are odd, then xy is odd.
If are in GP and are arithmetic mean of and respectively, then is equal to
Three numbers, of which the third is equal to , form a geometric progression. If is replaced with , then the three numbers form an arithmetic progression. Find these three numbers.
If 1b−c, 1c−a, 1a−b be consecutive terms of an A.P., then (b−c)2, (c−a)2, (a−b)2 will be in ___.
H.P
G.P
None of these
A.P
In how many ways 4 Indian and 4 Pakistani army Generals can be seated, half on each side of a long table, so that no two Indian Generals may be together?
(i) Find the number of sitting arrangements.
(ii) Do you feel that periodic meeting between senior officers and politicians are in the interest of both the countries for keeping peace and goodwill in the region? Express your views briefly.
If the sum of the roots of the equation ax2 + bx + c = 0 is equal to the sum of the squares of their reciprocals, then ac, ba, cb are in :
G.P.
H.P.
None
A.P.
If A(at2, 2at), B(at2, −2at) and C(a, 0), then 2a is equal to
A.M. of CA and CB
G.M. of CA and CB
H.M. of CA and CB
None of these
- 2
- 4
- 8
- 16
- a + d > b + c
- ad > bc
- None of these
Both (a) and (b)
In any Δ ABC, prove that
sin(B−C)sin(B+C)=(b2−c2)a2
Given HM of 2 numbers = 4 and 2A + G2 = 27. Use the relation G2 = AH with 2A + G2 = 27, to find A & G.
, 3
3, 9
, 3
, 9
- a2+c2>b2
- a2+b2>2c2
- a2+c2>2b2
- a2+b2>c2
- a=19
- a=24
- f(x)=0 has atleast one repeated root.
- b>0
- s>t and a101>b101
- s>t and a101<b101
- s<t and a101<b101
- s<t and a101>b101
If x, y, z∈R+ then xyx+y+yzy+z+xzx+z is always
≤2(x+y+z)
≤12(x+y+z)
≤4(x+y+z)
None of the above
- 15
- 8
- 11
- 20
- ac+bd>b2+c2
- a2+c2>b2+d2
- a2+d2>b2+c2
- ac+bd>b2+d2
If the aritmetic, geometric and harmonic menas between two positive real numbers be A, G and H, then