Equation of Plane Containing Two Lines

Q. If two lines
$\frac{x-1}{3}=\frac{y-2}{4}=\frac{z-3}{5}$ and
$\frac{x-9}{2}=\frac{y-8}{4}=\frac{z-7}{8}$
lie in the same plane then the equation of that plane is -

1. $3x-7y+z-1=0$
2. $9x-7y+z-1=0$
3. $6x-7y+2z-2=0$
4. None of these

Q. If two lines
$\frac{x-\alpha }{l}=\frac{y-\beta }{m}=\frac{z-\gamma }{n}$ and $\frac{x-{\alpha }^{\prime }}{l^{\prime }}=\frac{y-{\beta }^{\prime }}{m^{\prime }}=\frac{z-{\gamma }^{\prime }}{n^{\prime }}$
lie in the same plane then the equation of the plane is -

1. $\left|\begin{array}{ccc}x& y& z\\ l& m& n\\ l^{\prime }& m^{\prime }& n^{\prime }\end{array}\right|=0$
2. $\left|\begin{array}{ccc}x-\alpha & y-\beta & z-\gamma \\ l& m& n\\ l^{\prime }& m^{\prime }& n^{\prime }\end{array}\right|=0$
3. $\left|\begin{array}{ccc}l-l^{\prime }& m-m^{\prime }& n-n^{\prime }\\ l& m& n\\ l^{\prime }& m^{\prime }& n^{\prime }\end{array}\right|=0$
4. None of these

Q. Let the equation of the plane containing line $x-y-z-4=0=x+y+2z-4$ and parallel to the line of intersection of the planes $2x+3y+z=1$ and $x+3y+2z=2$ be $x+Ay+Bz+C=0$. Then the value of $|A+B+C-4|$ is