Factorial
Trending Questions
The value of 5! is _____
The sum of the digits in the unit place of all numbers formed with the help of taken all at a time is
- 17C10+19C11
- 17C10+19C11+17C11
- 17C10+20C11
- 19C10+19C11
In how many ways a team of 10 players out of 22 players can be made if 6 particular players are always to be included and 4 particular players are always excluded.
The number of numbers that can be formed by the digits 1, 2, 3, 4, 3, 2, 1 with the odd digits at odd places is
430
18
36
None of these
Make correct statements by filling in the symbols ⊂ or ⊄ in the blank spaces:
(i) {2, 3, 4} ..................... {1, 2, 3, 4, 5}
(ii) {a, b, c} ..................... {b, c, d}
(iii) {x : x is a student of Class XI of your school} ......... {x : x student of your school}
(iv) {x : x is a circle in the plane} ........... {x : x is a circle in the same plane with radius 1 unit}
(v) {x : x is a triangle in a plane} ........... {x : x is a rectangle in the same plane}
(vi) {x : x is an equilateral triangle in a plane} ............ {x : is a triangle in the same plane}
(vii) {x : x is an even natural number} .......... {x : x is an integer}
Find the remainder when 5k-1 is divided by 5, where k is a positive integer
- 2nCn
- 21⋅62⋅103⋅⋯4n−6n−1⋅4n−2n
- n+11⋅n+22⋅n+33⋅n+44⋅⋯2n−1n−1⋅2nn
- 2n[1⋅3⋅5⋯(2n−3)(2n−1)]n!
- 35
- 105
- 210
- 420
(i) p : For every positive real number x the number x−1 is also positive
(ii) q : All cats scratch
(iii) r : For every real number x, either x>1 or x<1
(iv) s : There exist a number x such that 0<x<1
(a) r !
(b) (r − 1) !
(c) (r + 1) !
(d) none of these.
Find the intersection of each of the following pairs of sets :
(i) X = {1, 3, 5} and Y = {1, 2, 3}
(ii) A = {a, e, i, o, u} and B = {a, b, c}
(iii) A = {x : x is a natural number and multiple of 3} and B = {x : x is a natural number less than 6}
(iv) A = {x : x is a natural number and 1 < x ≤ 6} and B = {x : is a natural number and 6 < x < 10}
(v) A = {1, 2, 3} and B=Φ
The sum of the digits in the unit place of all numbers formed with the help of 3, 4, 5, 6 taken all at a time is
18
432
108
144
The sum of the digits in the unit place of all numbers formed with the help of 3, 4, 5, 6 taken all at a time is
18
108
144
432
Eleven animals of a circus have to be placed in eleven cages one in each cage. If 4 of the cages are too small for 6 of the animals, find the number of ways of caging the animals.
- 8P4
- 8C4
- 4!×8C4
- 5!×8C5
The number of numbers that can be formed by the digits 1, 2, 3, 4, 3, 2, 1 with the odd digits at odd places is
430
36
18
None of these
The value of 2n{1.3.5.....(2n−3)(2n−1)} is
(2n)!n!
(2n)!2n
n!(2n)!
(2n−1)!n!
The value of 2n{1.3.5.....(2n−3)(2n−1)} is