Family of Planes Passing through the Intersection of Two Planes
Trending Questions
- x+y+z=0
- 17x+14y+11z=0
- 7x+4y+z=0
- 17x+14y+z=0
ax2+2hxy+by2=0 always represents a pair of straight lines passing through the origin. If
Column 1 Column 2
a. h2>ab 1. Lines are coincident
b. h2=ab 2. Lines are real and distinct
c. h2<ab 3. Lines are imaginary with real point of intersection i.e. (0, 0)
a-1 b-2 c-3
a-2 b-1 c-3
a-3 b-2 c-1
a-3 b-1 c-2
The equation of a plane passing through the line of intersection of the planes x+2y+3z=2 and x−y+z=3 and at a distance2√3from the point (3, 1, -1) is
5x−11y+z=17
√2x+y=3√2−1
x+y+z=√3
x−√2y=1−2√2
5x + 3y + 10z = 25. The equation of the plane in its new position is x – 4y + 6z = k, where k, is
- 106
- -89
- 73
- 37
The planes x-cy-bz=0, cx-y+az=0 and bx+ay-z=0 pass through a straight line, where a, b, c are non-zero constants. Then the value of a2+b2+c2+2abc is
-1
2
1
0