Focal Chord
Trending Questions
Q. Let PQ be a focal chord of the parabola y2=4ax. The tangents to the parabola at P and Q meet at a point lying on the line y=2x+a, a>0.
Length of chord PQ
Length of chord PQ
- 7a
- 5a
- 2a
- 3a
Q. If one end point of the focal chord of the parabola y2=4ax is (1, 2), then the other end point lies on
- x2y+2=0
- xy+2=0
- xy−2=0
- x2+xy−y−1=0
Q. If PSQ is the focal chord of the parabola y2=8x such that SP=6. Then the length of SQ is
- 6
- 4
- 3
- None of these
Q. If the point P(4, −2) is one end of the focal chord PQ of the parabola y2=x, then the slope of the tangent at Q is
Q. Equation of the parabola obtained by taking reflection of y=4x2−4x+3 about the line y=x, will be
- (y−12)2=14(x−2)
- (y−12)2=4(x−2)
- (y−2)2=14(x−12)
- (y−2)2=4(x−12)
Q. A line L passing through the focus of the parabola y2=4(x−1), intersects the parabola in two distinct points. If ′m′ be the slope of the line ′L′ then
- −1<m<1
- m<−1 or m>1
- m∈R
- None of the above
Q. The equation of common tangent to curve xy=−1 and y2=8x is
- 3y=9x+2
- y=2x+1
- 2y=x+8
- y=x+2
Q. Let PQ be a focal chord of the parabola y2=4ax. The tangents to the parabola at P and Q meet at a point lying on the line y=2x+a, a>0.
If chord PQ subtends an angle θ at the vertex of y2=4ax, then tan θ is equal to
If chord PQ subtends an angle θ at the vertex of y2=4ax, then tan θ is equal to
- 23√7
- −23√7
- 23√5
- −23√5
Q. If tangents are drawn to the parabola (x−3)2+(y+4)2=(3x−4y−6)225 at the extremities of the chord 2x−3y−18=0, then angle between tangents is
- 45∘
- 90∘
- 60∘
- 120∘
Q. The length of the intercept on the normal at the point (at2, 2at) of the parabola y2=4ax made by the circle which is described on the focal distance of the given point as diameter is
- a(1+t2)
- a√1+t2
- none of these
- √a(1+t2)
Q. The locus of the point of intersection of the tangents to the parabola y2=4ax which makes angles θ1 and θ2 with its axis so that cotθ1+cotθ2=k is
- kx−y=0
- kx−a=0
- y−ka=0
- x−ka=0
Q. If (xr, yr):r=1, 2, 3, 4 be the points of intersection of the parabola y2=4ax and the circle x2+y2+2gx+2fy+c=0, then
- y1+y2+y3+y4=0
- √x1+√x2+√x3+√x4=0
- y1−y2+y3−y4=0
- y1+y2−y3−y4=0