Graph of Quadratic Expression
Trending Questions
The equation of parabola whose focus is (– 3, 0) and directrix x + 5 = 0 is:
y2 = 4x
y2 = 4(x + 1)
y2 = 4(x + 4)
y2 = 4(x + 16)
What is the vertex of the quadratic function y = x2−6x+12?
(1, 1)
(2, 2)
(2, 3)
(3, 3)
If ax2 +bx+c=0 has no real roots and a+b+c<0, then
c 0
c < 0
c > 0
c = 0
For the quadratic equation x2 - (t - 3) x + t = 0 (t ∈ R), the values of 't' for which both the roots are greater than 2, are
[3, )
(- , -9]
[9, )
(- , 3]
(1+2m)x2−2(1+3m)x+4(1+m), x∈R, is always positive, is
- 8
- 7
- 6
- 3
- 2a+c>b
- a+2c>b
- 3a+c>4b
- a+3c<b
Which of the following options is/are true for the graph?
- a>0
- b>0
- b<0
- c<0
(a)
(b) (± 5/6, 0)
(c)
(d) none of these
then which of the following is/are correct?
- a>0
- b<0
- c>0
- D<0
If a, b, c ∈ R and a ≠ 0, c < 0, and if the quadratic equation ax2+bx+c = 0 has imaginary roots, then a + b + c is
Negative
Zero
Can't say
f(x)=−2x3−9x2−12x+1
The function f(x) is a decreasing function in the interval
- (−2, −1)
- (−1, ∞) only
- (−∞, −2)∪(−1, ∞)
- (−∞, −2) only
- c<0
- b>0
- a+b−c>0
- abc<0
Pick the correct plot for the function y=x2−2x+6
If a, b, c ϵ R and a ≠ 0, c > 0, the graph of f(x) = ax2+bx+c for which f(x)=0 has only imaginary roots, will look like
The line joining the origin to the points of intersection of the curves ax2+2hxy+by2+2gx=0 and a′x2+2h′xy+b′y2+2g′x=0 will be mutually perpendicular, if