Logarithmic Inequalities
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Fill in the blanks to make the statement true:.
The function t which maps temperature in degree Celsius to temperature in degree Fahrenheit is defined by t(C)=9C5+32. Find
(i) t(0) (ii) t(28) (iii) t(-10)
(iv) The value of C when t(C) = 212.
- x=y
- x>y
- None of these
- x<y
The value of , where stands for the number is
If
is differentiable at every point of the domain, then the values of and are respectively:
Solution set of log3(x2−2)<log3(32|x|−1) is
- (−√2, −1)
- (−2, −√2)
- (−√2, 2)
- None of these
Prove 1+2+3+⋯+n<18(2n+1)2.
In drilling world's deepest hole it was found that the temperature T in degree celcius, x km below the earth's surface was given by T = 30 + 2.5 (x -3), 3 ≤x≤15. It was assumed that this drilling resulted
5% increase in carbon dioxide level at a temperature above
205∘ and below 155∘C, so drillers tried to control the depth between these two limits. At what depth will the temperature be between 155∘ and 205∘ What values are depicted here by the drillers for selecting this temperature range ?
- x∈(1, ∞)
- x∈(−∞, 1]∪[2, ∞)
- x∈[2, ∞)
- x∈[1, 2]
- p+m+c=1920
- p+m+c=2720
- pmc=110
- pmc=14
- None
- 2
- 4
- 3
- -2
- 4
- x∈(√6, 6)
- x∈(√6, 4)
- x∈(√6, 3)
- x∈(3, 4)
Which is the larger fraction?
- (1, 2]
- [3, 4)
- (1, 3]
- (1, 4)
Solution set of the inequality log0.8(log6x2+xx+4)<0
(-4, -3)
(−3, 4)∪(8, ∞)
(−4, −3)∪(8, ∞)
(−3, ∞)
If a1, a2, a3, ........a24 are in arithmetic progression and a1 + a5 + a10 + a15 + a20 + a24 = 225, then find the value of
a1 + a2 + a3 + ..........+ a23 + a24
- (−2, −1)
- (1, 2)
- None
- (2, ∞)
If x∈R satisfies (log10100x)2+(log1010x)2+log10x≤14 then x contains the interval
(0, 10)
[10−92, 10]
(0, ∞)
(−1, ∞)
The set of real values x satisfying log0.3 (x-3)>3.
x>3
x>3.027
x > 0.027
x ∈ (3, 3.027)
- 11, ∞
- 1, 109
- 1, 10
- (199, ∞)
Find the set of real values of x for which log0.5log22x+1x+1>0
x ∈ (-1, )
x ∈ (1, )
x ∈ (2, )
x ∈ (0, )
- x>y
- x<y
- x=y
- None
The number is as much greater than as it is less than . Find the number.
- x∈(−∞, −1)∪(2, ∞)
- x∈(−∞, 1)∪[2, ∞)
- x∈(−∞, −1)
- x∈[2, ∞)
- A=log334
- A=log1/343
- B=log34
- B=log43
The solution set of the above inequality has integral values of x
If y=xlogx(a+bx) , then xnd2ydx2=(xdydx−y)m, where:
- 130
- 415
- 2930
- 1115