Second Derivative Test for Local Minimum
Trending Questions
Q. Let the function f be defined by f(x)=xlnx, for all x>0. Then
- f is increasing on (0, e−1)
- f is decreasing on (0, 1)
- The graph of f is concave down for all x
- The graph of f is concave up for all x
Q. Which of the following is (are) true about the function f(x)=−34x4−8x3−452x2+105 ?
- x = 0 is point of local maxima
- x = 0 is point of local minima
- x = –3 is point of local minima
- x = –5 is point of local maxima.
- x = –5 is point of local minima.
Q. Find the centre, the lengths of the axes, eccentricity, foci of the following ellipse:
(i) x2 + 2y2 − 2x + 12y + 10 = 0
(ii) x2 + 4y2 − 4x + 24y + 31 = 0
(iii) 4x2 + y2 − 8x + 2y + 1 = 0
(iv) 3x2 + 4y2 − 12x − 8y + 4 = 0
(v) 4x2 + 16y2 − 24x − 32y − 12 = 0
(vi) x2 + 4y2 − 2x = 0
(i) x2 + 2y2 − 2x + 12y + 10 = 0
(ii) x2 + 4y2 − 4x + 24y + 31 = 0
(iii) 4x2 + y2 − 8x + 2y + 1 = 0
(iv) 3x2 + 4y2 − 12x − 8y + 4 = 0
(v) 4x2 + 16y2 − 24x − 32y − 12 = 0
(vi) x2 + 4y2 − 2x = 0
Q. Let f(x) be a polynomial of degree 5 such that x=±1 are its critical points. If limx→0(2+f(x)x3)=4, then which of the following is not true ?
- f(1)−4f(−1)=4.
- x=1 is a point of maxima and x=−1 is a point of minimum of f.
- f is an odd function.
- x=1 is a point of minima and x=−1 is a point of maxima of f.
Q. Let f(x) be a polynomial of degree 5 such that x=±1 are its critical points. If limx→0(2+f(x)x3)=4, then which of the following is not true ?
- f is an odd function
- f(1)−4f(−1)=3
- x=1 is a point of maxima and x=−1 is a point of minimum of f
- x=1 is a point of minima and x=−1 is a point of maxima of f