Selecting Consecutive Terms in GP
Trending Questions
If the product of three numbers in GP is 216 and the sum of their products in pairs is 156, find the numbers.
For a, b, c to be in GP, what is the value of a−bb−c
The sum of first three terms of a G.P. is 3910 and their product is 1. Find the common ratio and the terms.
- xy
- √xy
- yx
- xy
If S be the sum, P be the product and R be the sum of the reciprocals of n terms in a GP, prove that P2=(SR)n
256, 512
512, 1023
512, 1024
256, 511
- If n is even, there are an even number of ordered pairs (i, j), such that p(i, j)=kl
- p(i, j)=kl for some i and j
- If n is odd, there are an even number of ordered pairs (i, j), such that p(i, j)=kl
- Whenever n is odd there is an i such that p(i, i)=kl
- 139
- 927
- 931
- 763
Find n, if the ratio of the fifth term from the beginning to fifth term from the end in the expansion of (4√2+14√3)n is √6:1.
Or
Prove that the coeffficient of the middle term in the expansion of (1+x)2n is equal to the sum of the coefficient of middle terms in the expansion of (1+x)2n−1.
[MNR 1978]
1, 3, 9
2, 6, 18
- 3, 9, 27
- 2, 4, 8
- 27
- −27
- −272
- 272
i) (a+b)2, (b+c)2, (c+d)2 are in G.P
ii) 1a2+b2, 1b2+c2, 1c2+d2 are in G.P
If a, b, c and d are in G.P show that (a2+b2+c2)(b2+c2+d2)=(ab+bc+cd)2.
- x ∊ (-1, ∞)
- none of these
Find the sum of the GP \((1+x)^{21}+(1+x)^{22}+......(1+x)^{30}
[MNR 1978]
- 2, 4, 8
1, 3, 9
2, 6, 18
- 3, 9, 27
If a, b, c, d are in GP, prove that
(a2+b2+c2)(b2+c2+d2)=(ab+bc+cd)2
- 18
- 12
- 4
- 16
- 36
- 32
- 28
- 24
If the arithmetic mean of two numbers be A and geometric mean be G, then the numbers will be