Standard Deviation about Mean
Trending Questions
Find the mean and variance for the data
6, 7, 10, 12, 13, 4, 8, 12
Find the mean and variance for the first n natural numbers.
For a frequency distribution consisting of 18 observations, the mean and the standard deviation were found to be 7 and 4 respectively. But on comparison with the original data, it was found that a figure 12 was miscopied as 21 in calculations. Find the correct mean and standard deviation.
- 1
- 3
- 5
- 7
- 20
- 16
- 18
- 22
Prove that the standard deviation of the first natural numbers is .
What do you understand by standard deviation?
If each of the observations x1, x2, x3, ⋯, xn is increased by an amount a, where a is a negative or positive number, then show that the variance remains unchanged.
Which of the following are true statements.
Variance gives a better picture of dispersion or scatter compared to mean deviation
Variance can be zero even if all observations are not equal.
For given n observation x1, x2, ... xn, with mean variance will be
Variance can be a negative quantity if all the observations are negative
Find the mean and variance for each of the data in Exercise 1 to 5:
xi 6 10 14 18 24 28 30 fi 2 4 7 12 8 4 3
Calculate the mean and the variance of first n natural numbers.
Find the value of n, so that an+1+bn+1an+bn is the geometric mean between a and b
Or
If f is a function satisfying f(x+y)=f(x)f(y) for all x, y∈N such that f(1)=3 and ∑nx=1f(x)=120 find the value of n.
- 9, 4
- 7, 6
- 6, 5
- 10, 3
The standard deviation of the first n natural numbers is
n+12
√n(n+1)2
√n2−112
none of these
Standard deviation for x1, x2, .....xn about mean can be expressed as √1n∑ni=1(xi−¯x)2.
False
True
- 80
- 25
- 20
- 16
xi | 10 | 15 | 18 | 20 | 25 |
fi | 3 | 2 | 5 | 8 | 2 |
- 14
- 15
- 16
- 17
A scientist is weighing each of 30 fishes. Their mean weight worked out is 30 gm and a standard deviaiton of 2 gm. Later, it was found that the measuring scale was misaligned and always under-reported every fish weight by 2gm. The correct mean and standard deviation (in gm) of fishes are respectively:
32, 4
28, 4
32, 2
28, 2
Standard deviation for x1, x2, .....xn about mean can be expressed as √1n∑ni=1(xi−¯x)2.
True
False
- ∑ni=1(xi−¯¯¯¯¯X)2
- 1n∑ni=1(xi−¯¯¯¯¯X)2
- √1n∑ni=1(xi−¯¯¯¯¯X)2
- √1n∑ni=1xi2+¯¯¯¯¯X2
- √10
- √3
- √2
- √5
For observations x1, x2, x3, .........., xn, if ∑ni=1(xi+1)2=9n and ∑ni=1(xi−1)2=5n., then standard deviation of the data is
√3
√5
√2
√10
- 23.23
- 25.33
- 46.66
- 93.32
Given that (¯¯¯x) is the mean and σ2 is the variance of n observations x1, x2, ....xn. Prove that the mean and variance of the observations ax1, ax2, ax3...axnare a¯¯¯x and a2σ2 respectively (a≠0)
The standard deviation of 4 consecutive numbers which are in A.P is √5. The common difference (d) of this A.P is
±√5
±2√5
±2
±√2
- 10:3
- 4:9
- 5:8
- 6:7