Variable Separable Method
Trending Questions
Q.
Prove that cosx(1−sin x)=tan (π4+x2)
Q.
The solution of the differential equation dydx=sec x (sec x+tan x) is
y = sec x + tan x + c.
y = sec x + cot x + c.
y = sec x - tan x + c
None of these
Q.
The differential equations satisfied by the system of parabolas is:
Q. The Cartesian coordinates (x, y) of a point on a curve are given by x:y:1=t3:t2−3:t−1 where t is a parameter, then the points given by t = a, b, c are collinear, if
- abc + 3(a + b + c) = ab + bc + ca
- 3abc + 2(a + b + c) = ab + bc + ca
- abc + 2(a + b + c) = 3(ab + bc + ca)
- None of the above
Q. Given that the slope of the tangent to a curve y=y(x) at any point (x, y) is 2yx2. If the curve passes through the centre of the circle x2+y2−2x−2y=0, then its equation is :
- xloge|y|=2(x−1)
- xloge|y|=(x−1)
- xloge|y|=−2(x−1)
- x2loge|y|=−2(x−1)
Q. The equation of the curve which passes through the point (2a, a) and for which the sum of the Cartesian sub tangent and the abscissa is equal to the constant a is
- y(x−a)=a2
- y(x+a)=a2
- x(y−a)=a2
- x(y+a)=a2
Q. The equation of the curve passing through the origin and satisfying the differential equation (dydx)2=(x−y)2, is
- e2x(1−x+y)=1+x−y
- e2x(1+x−y)=1−x+y
- e2x(1−x+y)=1+x+y
- e2x(1+x+y)=1−x+y
Q. If xexy−y−sin2x=0 then dydx at x=0 is
Q.
The solution of the differential equation dydx=1+x+y+xy is
log(1+y)=x+x22+c
- (1+y)2=x+x22+c
- log(1+y)=log(1+x)+c
None of these
Q. If the curve y=y(x) satisfies the differential equation y−xdydx=a(y2+dydx) and always passes through a fixed point (1, 1), then the total number of possible values of a is
(Assume the constant of integration to be zero)
(Assume the constant of integration to be zero)
Q. Minimum distance between the curves y2=4x&x2+y2−12x+31=0 is
- √21
- √26−√5
- √20−√5
- √21−√5
Q. Let f be a twice differentiable function on R such that t2f(x)−2tf′(x)+f′′(x)=0 has two equal values of t for all x and f(0)=1, f′(0)=2. Then the value of 3limx→0(f(x)−1x−t2) is
Q. If dydx+3cos2xy=1cos2x, x∈(−π3, π3), and y(π4)=43, then y(−π4) equals :
- −43
- 13+e6
- 13+e3
- 13
Q. Let C1 be the curve obtained by solution of differential equation 2xydydx=y2−x2, x>0. Let the curve C2 be the solution of 2xyx2−y2=dydx. If both the curves pass through (1, 1), then the area enclosed by the curves C1 and C2 is equal to :
- π+1
- π−1
- π4+1
- π2−1
Q. The general solution of the differential equation ydx−xdy+lnxdx=0 is
(where C is constant of integration)
(where C is constant of integration)
- y+lnx−1=C
- y+lnx−1=Cx
- y+lnx+1=Cx
- y−lnx−1=C
Q. Which of the following differential equations can be solved using variable separable method.
1. (x2+y2)dx−2xydy=0
2. (x2+sinx)dx+(siny)dy=0
1. (x2+y2)dx−2xydy=0
2. (x2+sinx)dx+(siny)dy=0
- Only 1
- Only 2
- Both 1 and 2
- None of the above
Q. If |z−2+2i|=1, then
- maximum value of |z| is √8+1
- maximum value of |z| is √10+1
- minimum value of |z| is √8−1
- minimum value of |z| is √6−1
Q. Let y=y(x) be a solution of the differential equation, √1−x2dydx+√1−y2=0, |x|<1.
If y(12)=√32, then y(−1√2) is equal to:
If y(12)=√32, then y(−1√2) is equal to:
- −1√2
- −√32
- 1√2
- √32
Q. The population P=P(t) at time ‘t′ of a certain species follows the differential equation dPdt=0.5P−450. If P(0)=850, then the time at which population becomes zero is :
- 12loge18
- 2loge18
- loge9
- loge18