Vertices of Ellipse

Q.

Find the coordinates of the focus and the vertex, the equations of the directrix, the axis, and length of latus rectum of the parabola $x^2=-16y.$

Q. The equation of the ellipse whose vertices are (–4, 1), (6, 1) and one latus rectum is x – 4 = 0 is

1. 
2. 
3. 
4. 

Q.

Find the coordinates of the focus, axis of the parabola, the equation of the directrix and the length of the latus rectum.
$x^2=-16y$

Q.

Find the coordinates of the foci, the vertices, the length of major axis, the minor axis, the eccentricity and the length of the latus rectum of the ellipse.
$4x^2+9y^2=36$

Q.

The vertices of the ellipse $\frac{(x+1{)}^2}{25}+\frac{(y-3{)}^2}{16}$ = 1 is

1. (3, 4) and (-6, 3)

2. (4, 3) and (-6, 3)

3. (5, 3) and (-7, 3)

4. (6, 3) and (-8, 3)

Q.

If the foci and vertices of an ellipse be (±1, 0) and ( ±2, 0) , then the minor axis of the ellipse os

1. $2\sqrt{5}$

2. 2

3. 4

4. $2\sqrt{3}$

Q.

The equation of the ellipse whose vertices are ( ±5, 0) and foci are ( ± 4 , 0 ) is

1. $9x^2+25y^2=225.$

2. $25x^2+9y^2=225.$

3. $3x^2+4y^2=192.$

4. None of these

Q. The equation of the ellipse whose vertices are (–4, 1), (6, 1) and one latus rectum is x – 4 = 0 is

1. $\frac{(x-1{)}^2}{25}+\frac{(y-1{)}^2}{16}=1$
2. $\frac{(x-1{)}^2}{16}+\frac{(y-1{)}^2}{25}=1$
3. $\frac{(x+1{)}^2}{25}+\frac{(y+1{)}^2}{16}=1$
4. $\frac{(x+1{)}^2}{16}+\frac{(y+1{)}^2}{25}=1$