1st Equation of Motion
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A block of mass M is placed on the top of a bigger block of mass 10 M as shown in figure.All the surfaces are frictionless. The system is released from rest. Find the distance moved by the bigger block at the instant the smaller block reaches the fround.
0.2m
0.1m
0.3m
0.4m
A small sphere of mass m is dropped from a great height. After it has fallen 100 m, it has attained its terminal velocity and continues to fall at that speed. The work done by air friction against the sphere during the first 100 m of fall is
Greater than the work done by air friction in the second 100 m
Less than the work done by air friction in the second 100 m
Equal to 100 mg
Greater than 100 mg
A body under the action of several forces will have zero acceleration
When the body is very light
When the body is very heavy
When the vector sum of all the forces acting on it is zero
When the body is a point body
- t=22 s
- t=8 s
- t=12 s
- t=16 s
A car moving at a speed u is stopped in a certain distance when the brakes produce a deceleration a. If the speed of the car is nu, what must be the deceleration of the car to stop it in the same distance?
A coin is dropped in a lift. It takes time t1 to reach the floor when lift is stationary. It takes time t2 when lift is moving up with constant acceleration. Then
t1 > t2
t2 > t1
t1 = t2
t1 >> t2
Two students were asked to plot a distance-time graph for the motion described by Table A and Table B. The graph given in Figure is true for
Table A \begin{tabular}{|c|c|c|c|c|c|c|} \hline Distance moved \( ( m ) \) & 0 & 10 & 20 & 30 & 40 & 50 \\ \hline Time (minutes) & 0 & 2 & 4 & 6 & 8 & 10 \\ \hline \end{tabular} Table B \begin{tabular}{|c|c|c|c|c|c|c|} \hline Distance moved (m) & 0 & 5 & 10 & 15 & 20 & 25 \\ \hline Time (minutes) & 0 & 1 & 2 & 3 & 4 & 5 \\ \hline \end{tabular}
Fig 13.2
A car moving with a speed of 50 km/h can be stopped by applying brakes after at least 10 m. What will the minimum stopping distance if the same car is moving at a speed of 100 km/h?
40. 1 m
25.4 m
30 m
20.2 m