3rd Equation of Motion
Trending Questions
A bullet on penetrating into its target loses its velocity by . What additional distance will it penetrate into the target before it comes to rest?
The velocity of kerosene oil in a horizontal pipe is 5 m/s. If then the velocity head of oil will be
1.25 m
12.5 m
125 m
0.125 m
- s1=13s2=15s3
- s1=15s2=13s3
- 2s1=13s2=15s3
- s1=16s2=15s3
(a) is 0⋅20 kg-m2
(b) is 0⋅40 kg-m2
(c) is kg-m2
(d) cannot be deduced with this information.
- 50 m
- 60 m
- 70 m
- 80 m
- 11.75 m
- 13.75 m
- 15.75 m
- 18.75 m
A bullet moving with a velocity of 200 cm/s penetrates a wooden block and comes to rest after traversing 4 cm inside it. What velocity is needed for travelling distance of 9 cm in same block?
100 cm/s
136.2 cm/s
300 cm/s
250 cm/s
- 21.4
- 34.33
- 25.5
- 30.7
- 1.5 cm
- 1.0 cm
- 3.0 cm
- 2.0 cm
- v+u2
- 2uv4+v
- √u2+v22
- v−u2
- 650 m
- 750 m
- 700 m
- 800 m
- 300 K, 500 K
- 500 K, 300 K
- 375 K, 300 K
- 300 K, 375 K
- 3 s
- 5 s
- 7 s
- 9 s
- √120 ms−1
- √240 ms−1
- √360 ms−1
- √180 ms−1
- −12.5 ms−2
- 24.5 ms−2
- −6.25 ms−2
- 6.25 ms−2
- H=(x+y)2/4x
- H=(x+y)2/4y
- H=(x+y)2/2x
- H=(x+y)2/2y
- 40 m
- 25 m
- 10 m
- 45 m
- 4.25 ms−2
- 6.30 ms−2
- 5.25 ms−2
- 5.65 ms−2
A charged body is kept in an electric field where it experiences a constant acceleration of 10 m/s2 in the positive x-direction. The body hits wall after travelling 4 m and rebounds but can travel only upto 2 m before coming to rest momentarily . If the body was in contact with the wall for 12 ms then find the average acceleration of it due to the impact?
+1.26×103m/s2
+10m/s2
−10m/s2
−1.26×103m/s2
- √98
- √40
- √20
- √12
- vx2h
- 2vxh
- 2vxh
- 0.01v