Addition and Subtraction in Unit Vector Notation
Trending Questions
Can we add 2 vectors of unequal magnitudes and get a zero vector?
True
False
If , then
Vector →A is 2 cm long and is 60∘ above the +ve X axis. Vector →A is 2 cm long and is 60∘ below the x - axis in the fourth quadrant. The value of →A + →B is
2 cm along -x axis
2 cm along +x axis
4 cm along -x axis
4 cm along +x axis
- 60∘
- Zero
- 90∘
- None of these
Magnitude of vector which comes on addition of two vectors, 6^i+7^j and 3^i+4^j is
√136
√13.2
√202
√160
If are respectively the magnitudes of the vectors , then the correct order of is;
- 18^i−6^j
- 32^i−13^j
- −18^i+6^j
- −25^i+13^j
The position vector of a particle is →r=(a cos ωt)^i+(a sin ωt)^j. The velocity of the particle is
Parallel to the position vector
Perpendicular to the position vector
Directed towards the origin
Directed away from the origin
- 2 along +y-axis
- 2 along +x-axis
- 1 along -x-axis
- 2 along -x-axis
The position vector of a particle is determined by the expression
→r=3t2^i+4t2^j+7^k. The distance traversed in first 10 sec is
500 m
300 m
150 m
100 m
What vector must be added to the two vectors ^i−2^j+2^kand2^i+^j−^k, so that the resultant may be a unit vector along x-axis
2^i+→j−→k
−2^i+→j−→k
2^i−→j+→k
−2^i−→j−→k
- −23
- 12
- 23
- 2
Vectors A and B are 6^i−7^j+6^k and 3^i+4^j+6^k respectively. Their vector difference in unit vector notation will be
9^i−3^j+12^k
9^i−11^j+12^k
10^i−^j−^k
3^i−11^j+0^k
Then select the correct relation.
- AB=CD
- AB=12CD
- AB=23CD
- AB=14CD
Add vectors A & D. Which of these is the correct result?
4^i
0^i
−1^i
None of these
The unit vector parallel to the resultant of the vectors
→A=4^i+3^j+6^k and
→B=−^i+3^j−8^k is
17(3^i+6^j−2^k)
17(3^i+6^j+2^k)
149(3^i+6^j−2^k)
149(3^i−6^j+2^k)
- ^r=1√3(^i+^j−^k)
- ^r=1√2(^i+^j−^k)
- ^r=13(^i+^j−^k)
- ^r=1√3(^i+^j+^k)
- 2 cm along + y - axis
- 2√3 cm along + y - axis
- 1 cm along - x- axis
- 2 cm along - x - axis
- 4^i+6^j
- 4^i−^j
- −4^i+6^j
- −4^i−6^j
→A are
- 2√45, 4√45 and 5√45
- 1√45, 2√45 and 3√45
- 4√45, 0 and 4√45
- 3√45, 2√45 and 5√45
- Perpendicular
- Parallel
- Antiparallel
- Inclined at an angle of 60∘
→A=2^i+^j, 3^j−^k and →C=6^i−2^k. Value of →A−2→B+3→C would be
20^i−5^j+4^k
20^i−5^j−4^k
4^i+5^j+20^k
5^i+4^j+10^k
→A is a vector which when added to the resultant of vectors (2^i−3^j+4^k) and (^i+5^j+2^k) yields a unit vector along the y-axis. Then vector →A is
−3^i−^j−6^k
3^i+^j−^k
−3^i−^j+6^k
3^i+^j+6^k
The three vectors →A=3^i−2^j+^k, →B=^i−3^j+5^k and →C=2^i+^j−4^k form
An equilateral triangle
Isosceles triangle
A right angled triangle
No triangle
Given that →A+→B=→C and that →C is ⊥ to →A. Further if |→A|=|→C|, then what is the angle between →A and →B
π4radian
π2radian
3π4radian
πradian
- −23
- 12
- 23
- 2